Question

I need help. Can you please explain to me how to do this?

Answer 1

The solution of given system of equations is

x=8, y=3

Step-by-step explanation:

Given equations are:

$-2x+9y=11\ \ \ \ \ Eqn\ 1-5x+2y=-34\ \ \ \ \ Eqn\ 2$

Multiplying eqn 1 by 5

$-10x+45y=55\ \ \ \ Eqn\ 3$

Multiplying eqn 2 by 2

$-10x+4y=-68\ \ \ \ Eqn 4$

Subtracting eqn 4 from eqn 3

$-10x+45y-(-10x+4y)=55-(-68)\\-10x+45y+10x-4y=55+68\\41y=123$

Dividing both sides by 41

$\frac{41y}{41}=\frac{123}{41}\\y=3$

Putting y=3 in equation 1

$-2x+9(3)=11\\-2x+27=11\\-2x=11-27\\-2x=-16$

Dividing both sides by -2

$\frac{-2x}{-2}=\frac{-16}{-2}\\x=8$

Hence,

The solution of given system of equations is

x=8, y=3

Keywords: Linear equations, Variables

Learn more about linear equations at:

• brainly.com/question/8224301
• brainly.com/question/8180193

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