Answer:
13 in³
Step-by-step explanation:
This is a skewed pyramid, but that doesn't change the way you find the volume of the figure.
The formula for the volume of a pyramid is 1/3(b)(h)
Multiply 6 by 6.5 to get 39, then divide it by 3 to get 13 in³
Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
1.<span>
The midpoint </span>MPQ of PQ is given by (a + c /
2, b + d / 2)<span>
2.
Let the x coordinates of the vertices of P_1 be :
x1, x2, x3,…x33
the x coordinates of P_2 be :
</span>z1, x2, x3,…z33<span>
and the x coordinates of P_3 be:
w1, w2, w3,…w33</span>
<span>
3.
We are given with:
</span>
X1
+ x2 + x3… + x33 = 99
We also want to find the value of w1 + w2 + w3… + w33.<span>
4.
Now, based from the midpoint formula:</span>
Z1 = (x1 + x2) / 2
Z2 = (x2 + x3) / 2
Z3 = (x3 + x4) / 2
Z33 = (x33 + x1) / 2<span>
and
</span>
<span>W1
= (z1 + z1) / 2
W2 = (z2 + z3) / 2</span>
<span>W3
= (z3 + z4) / 2
W13 = (z33 + z1) / 2
.
.
5.</span>
<span>W1
+ w1 + w3… + w33 = (z1 + z1) / 2 + (z2 +
z3) / 2 + (z33 + z1) / 2 = 2 (z1 + z2 + z3… + z33) / 2</span>
<span>Z1
+ z1 + z3… + z33 = (x1 + x2) / 2 + (x2 + x3) / 2
+ (x33 + x1) / 2
</span>2 (x1 + x2 + x3… + x33) / 2 = (x1 + x2 +
x3… + x33 = 99<span>
<span>Answer: 99</span></span>
You have the original function as 2x-5
and you are given the value of x to be -1/2
Therefore, all you have to do is substitute the value of x in the function and calculate it as follows:
f(-1/2) = 2(-1/2) - 5 = -1 -5 = -6
Answer:
Domain: [3, ∞)
Range: [-1, ∞)
Step-by-step explanation:
lmk if you want an explanation
