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Kipish [7]
3 years ago
7

There are 2 miners. One mines 19,687 m of ore in 1 hour and the other one mines the same amount of ore in 51 minutes. Find how m

uch ore per hour the second miner gets.
Mathematics
2 answers:
kkurt [141]3 years ago
7 0
19687/51 = 386.02 per minute

in 60 minutes.....386.02 * 60 = 23161.2
k0ka [10]3 years ago
4 0
60/51 x 19687=23161.18
23161.18-19687=3474.18
☺☺☺☺
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7 0
3 years ago
2x+5=10<br> I need to find out x pls help​
Finger [1]

Answer:

5

Step-by-step explanation:

2x + 5 = 10

you minus the 5

2x = 5

you divide both sides by 2

x = 5

7 0
3 years ago
Read 2 more answers
Simplify 6 - 3(4 - 3x)<br> -3x - 6<br> 9x + 18<br> 9x - 6
svet-max [94.6K]

Answer:

6 (19 x - 2)

Step-by-step explanation:

Simplify the following:

6 - 3 (4 - 3 x) - 3 x - 6×9 x + 18×9 x - 6

-6×9 = -54:

6 - 3 (4 - 3 x) - 3 x + -54 x + 18×9 x - 6

18×9 = 162:

6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6

Grouping like terms, 6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6 = (-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6):

(-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6)

-3 x - 54 x + 162 x = 105 x:

105 x - 3 (4 - 3 x) + (6 - 6)

6 - 6 = 0:

105 x - 3 (4 - 3 x)

-3 (4 - 3 x) = 9 x - 12:

9 x - 12 + 105 x

Grouping like terms, 105 x + 9 x - 12 = (105 x + 9 x) - 12:

(105 x + 9 x) - 12

105 x + 9 x = 114 x:

114 x - 12

Factor 6 out of 114 x - 12:

Answer: 6 (19 x - 2)

7 0
3 years ago
A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a
DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}

Then the mean (first moment) is

E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710

and the second moment is

E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3

The second moment is useful in finding the variance, which is given by

V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3

You get the standard deviation by taking the square root of the variance, and so

\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09

8 0
3 years ago
Complete the ratio table below to show ratios equivalent to 4:18.
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The blanks are weird. I don't understand them!
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3 years ago
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