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Salsk061 [2.6K]
3 years ago
8

What type of reproduction occurs when animals produce cloned offspring

Biology
1 answer:
gtnhenbr [62]3 years ago
8 0
This is called asexual reproduction.
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Alcohol like ethanol
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i need help thinking of an idea for an enviormental science experiment. please help i need an idea by friday!!!!!!!!!
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Pollution is always a good way to go but you don't have to do air pollution you can do water pollution or both air and water pollution.

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3 years ago
A mouse geneticist selected for increased 12-day litter weight (total weight of a litter of offspring 12 days after birth) in a
wlad13 [49]

Answer:

12-day litter weight is a trait that has an important genetic influence and therefore also a high response to selection

Explanation:

Heritability is a statistical measure of how much of the variation in a given trait can be attributed to genetic differences and how much of trait variation is due to environmental factors. A heritability value close to 1 indicates that almost all of the variability is due to genetic factors, while being poorly influenced by environmental factors. In this case, 12-day litter weight is a trait that exhibits an important genetic component (i.e., a high heritability value), thereby the correlation between parent and offspring will be high and lines selected for this trait will show a high response to selection.

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2 years ago
How are food chains and food webs and food webs similar? How are they different?
tatuchka [14]
They all go through a rotation in which one needs another
4 0
3 years ago
HELP ASAP I WILL GIVE BRAINLIST
adelina 88 [10]

Answer:

1) CO₂

2) 0.2551 g

Explanation:

The balanced reactions are:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂

1) The gas produced is CO₂.

2) Calculate mass of CaCO₃:

(0.5236 g) (0.4230) = 0.2215 g CaCO₃

Convert to moles:

(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃

Find moles of CaCO₃:

(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂

Convert to mass:

(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂

Calculate mass of MgCO₃:

(0.5236 g) (0.5770) = 0.3021 g MgCO₃

Convert to moles:

(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃

Find moles of MgCO₃:

(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂

Convert to mass:

(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂

Total mass of CO₂:

0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂

8 0
3 years ago
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