Answer:
x^2 + 2xy + y ^2
Step-by-step explanation:
A = a^2
a = x + y
(x + y) + (x + y)
x^2 + xy + xy + y^2
x^2 + 2xy + y ^2
<h2>true</h2>
I did it on my calculater and the answer came as 13
hope that helps :)
Assuming the order required is as n-> inf.
As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.
We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).
So yes, both are o(log(n)).
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.9 1/2 cups is equal to 19/4. divide 19 by 3 (the 3 from 3/4) and you get 6 1/4. Skylar can make 6 batches with this one bag of sugar.
