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3 years ago

Can someone solve for x??

Mathematics

1 answer:

miskamm [114]3 years ago

7 0

Sum of interior angle of polygon: S = (n-2) * 180°,

where n is number of sides and where S is total degrees.

With 6 sides, n = (6-2)*180 = 720°

Then set all of the interior equations equal to the sum, or

720 = 5x + 4x+2 + 5x+6 + 2x-2 + 3x+5 + x-10

720 = 20x + 1

719 = 20x

x = $\frac{719}{20}$ = 35.95

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I need help with my quiz what is 100×100

creativ13 [48]

Answer:

10000 (Typo)

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

What is the approximate diameter of a sphere with a volume of 34 cm

Nutka1998 [239]

Answer:

<h3>The diameter is 4cm</h3>

Step-by-step explanation:

Volume of a sphere is

$V = \frac{4}{3} \pi {r}^{3}$

Where r is the radius

diameter = radius × 2

To find the diameter we must first find the radius

Volume = 34cm³

That's

$34 = \frac{4}{3} \pi {r}^{3} \\ \\ 34 \times 3 = 4\pi {r}^{3} \\ \\ 102 = 4\pi {r}^{3} \\ {r}^{3} = \frac{102}{4} \pi \\ \\ r = \sqrt[3]{ \frac{51}{2\pi}} \\ \\ r = 2.01 \\ \\ r = 2.0 cm$

Diameter = 2 × 2cm

Hope this helps you

6 0

3 years ago

How do you do #1 & #2 ?

Alexeev081 [22]

$Answer: \\ 1. \: x = \frac{ {32}^{2} }{24} = \frac{128}{3} \\y = \sqrt{ {24}^{2} + {32}^{2} } = 40\\ z = \frac{32 \times 40}{24} = \frac{160}{3} \\ \\ 2. \: x = \sqrt{( {4 \sqrt{5} )}^{2} - {8}^{2} } = 4$

7 0

3 years ago

How to solve exterior angles

maks197457 [2]

The exterior angle of a triangle is equal to the sum of the other 2 oposite interior angles
therfor

95=4x-8+3x-18
95=7x-24
add 24 both sides
119=7x
divide both sides by 7
17=x

sub back

4x-8
4(17)-8
68-8
60=∠F

3x-16
3(17)-16
51-16
35=∠G

5 0

3 years ago

A book with 650 pages has 3 pages with diagrams.

Mrac [35]

The pages that have diagrams is an illustration of proportions

0.46% pages have diagrams

<h3>How to determine the percentage</h3>

The given parameters are:

Total = 650 pages

Diagrams = 3 pages

The percentage of page that has diagram is then calculated as:

$Diagram\% = \frac{Diagrams}{Total} * 100\%$