The digit 5 does because it is in the same place value.
Sqrt(2) = 1.41
so it would be between 1 and 2
Answer is A
Answer:
Step-by-step explanation:
<span>The first step you need to do is to rewrite
x+y=3
as y=3-x
</span><span>Now we can replace the y in the equation with our newfound value for y, which is
y=3-x.
So lets write it now like this
Q=x^2+2(3-y)^2
=x^2+18-12x+2x^2
=3x^2+18-12x
</span>Hope this helps
