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velikii [3]
3 years ago
10

Which group of ordered pairs are on the line given by the equation 5x-2y

Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0
(0,0),(1,5/3),(2,10/3)
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“7a - 17 = 4a +1”<br><br> Step by step pls
Monica [59]

Answer:

a = 6

Step-by-step explanation:

7a-17 = 4a +1 ; Subtract 4a from both sides

3a - 17 = 1 ; Add 17 to both sides

3a = 18 ; Divide both sides by 3

a = 6

6 0
3 years ago
Read 2 more answers
If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

#SPJ10

5 0
2 years ago
The total weight of three tables is 16.9 pounds. The first table is twice as heavy as the second table and the weight of the thi
Degger [83]
Refer to image for answer

3 0
3 years ago
At the beach, Pancho and his sister both built sandcastles and then measured their heights. Pancho's sandcastle was 3/5 of a foo
lord [1]

1/5 of a foot

Simply subtract the height of Pancho’s sandcastle (3/5 of a foot) minus the height of his sister’s sandcastle (2/5 of a foot) to find a difference of 1/5 of a foot, meaning Pancho’s sandcastle was 1/5 of a foot taller than his sister’s sandcastle.

7 0
3 years ago
What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)
Pepsi [2]

Answer:

Vertical Asymptote:

x=1

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

f(x)=log_3(x-1)

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

x-1=0

we get

x=1

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

\lim_{x \to \infty}  f(x)= \lim_{x \to \infty}log_3(x-1)

\lim_{x \to \infty}  f(x)=log_3(\infty-1)

\lim_{x \to \infty}  f(x)=undefined

so, it does not exist

7 0
3 years ago
Read 2 more answers
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