Answer:
a. The possible dimensions of the total area are;
The width of the total area is (2·x + 8) inches
The length of the total area is (2·x + 10) inches
b. The dimensions of the photos are as follows;
The length of the photos are 10 inches
The width of the photos are 8 inches
Step-by-step explanation:
a. Given that the area, A = 4·x² + 36·x + 80
We get;
A = 4 × (x² + 9·x + 20) = 4 × (x + 4) × (x + 5) = (2·x + 8)·(2·x + 10)
Therefore, the possible dimensions of the total area (photo + mat) are;
The width of the total area (photo + mat) = (2·x + 8) in.
The length of the total area (photo + mat) = (2·x + 10) in.
b. The dimensions of the photos alone are shorter than the dimensions of the photo and mat combined by 2·x each
Therefore, we have the dimensions of the photos are as follows;
The length of the photo = (2·x + 10) in. - 2·x in. = 10 in.
The width of the photos = (2·x + 8) in. - 2·x in. = 8 in.
Answer:
The answer is 36
Step-by-step explanation:
Because 39+1=40
So then 40-24=16
and then divided by 6 is 36 because when you divide you multiply
15$ .. 3$ 12 more dollars left - you can only buy 3 boooks !
Answer:
Domain: {-2,0,-1,4}
Range: {4,2,3,-2}
Step-by-step explanation:
1. Given the The relation Q={ (-2, 4), (0, 2), (-1, 3), (4, -2)}, you can determine the domain and the range as following:
DOMAIN:
The domain is the x-coordinate of each ordered pair. Therefore, you have:
Domain: {-2,0,-1,4}
RANGE:
The range is the y-coordinate of each ordered pair. Therefore, you have:
Range: {4,2,3,-2}
I agree if you divide it. The answer will be 26.8
