Question

PLEASE HELP ME I BEG

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

• 1 + cot²x = csc²x

Consider the left side

$csc^{4}$ x - $cot^{4}$ x

Factorise as a difference of squares

= (csc²x - cot²x)(csc²x + cot²x)

= (1 + cot²x - cot²x)(csc²x + cot²x)

= csc²x + cot²x

= csc²x + csc²x - 1

= 2csc²x - 1 = right side ⇒ verified