Question

Determine the diameter, to the nearest inch, of a large can of tuna fish that has a volume of 66 inches and a height of 3.3 inches.

Answer 1

The diameter of the tuna fish is 5.048 inches, If it has a volume of 66 inches and a height of 3.3 inches.

Step-by-step explanation:

The given is,

         A volume of tuna fish is 66 inches

         Height of tuna fish is 3.3 inches

Step:1

        Let, V - Volume of the tuna fish

               h - Height of tuna fish

        Where,

               V - 66 cubic inches

               h - 3.3 inches

Step:2

      Formula to calculate the area is,

                Area, $A = \frac{Volume}{Height}$

                              = $\frac{66}{3.3}$

                          A = 20 square inches

Step:3

     Formula to calculate the radius,

                     Radius,  $r^{2} = \frac{A}{\pi }$

                                   $r^{2}$ = $\frac{20}{3.14}$

                                    r  = $\sqrt{6.36943}$

                                   r = 2.524 inches

Step:4

       Formula to calculate the diameter,

                                    $d=2r$

                                       = 2 × 2.524

                                  d = 5.048 inches

Result:

       Thus the diameter of the tuna fish is 5.048 inches, If it has a volume of 66 inches and a height of 3.3 inches.