Answer:
9442 lb
Step-by-step explanation:
First find the volume of the tank. This being a sphere, the volume is V =(4/3)π·r³. Here the diameter is 17 ft, so the radius, r, is half that: 8.5 ft.
Then the volume of the sphere is V = (4/3)π·(8.5 ft)³, and half that (the volume of the hemisphere) is (2/3)π·72.25 ft³.
Water weighs 62.4 lb/ft³. To find the weight of the water in the full tank, multiply the tank volume by this weight density 62.4 lb/ft³:
×
(2/3)π·72.25 ft³ · 62.4 lb/ft³ ≈ 9442 lb
The problem would be, 10+6x=4-4x. Then solve the problem by adding or subtracting the lowest variable to the other side and figure out the rest, if you can.
Answer:
x = 11°
Step-by-step explanation:
The parallel lines suggest we look to the relationships involving angles and transversals. The angle marked 33° and ∠CAB are alternate interior angles, hence congruent:
∠CAB = 33°
5x is the measure of the external angle opposite that internal angle and angle 2x of ΔABC, so it is equal to their sum:
5x = 2x + 33°
3x = 33° . . . . . . . . . subtract 2x
x = 11° . . . . . . . . . . . divide by 3
16:40 as a fraction is 16/40. 16/40 is 4/10 simplified
Density = mass / volume.
Volume = Final reading - Initial reading = 7 - 2 = 5 cm^3
Hence,
D = 25 / 5 = 5 g/cm^3
<span>Remember, cubic centimeters is a volume unit (the same volume as 1 milliliter)</span>
Hope that helped!