9514 1404 393
Answer:
1731 ft
Step-by-step explanation:
The tangent relation is useful in this problem.
Tan = Opposite/Adjacent
The height of the light is found to be ...
tan(11°) = height/(639 ft)
height = (639 ft)·tan(11°) . . . . . solve for height
Then the distance from the light to point B is ...
tan(3°) = height/(B distance)
B distance = height/tan(3°) = (639 ft)·tan(11°)/tan(3°) ≈ 2370 ft
Then the distance from point A to point B is ...
2370 ft -639 ft = 1731 ft . . . AB distance
Answer:
Freshman = 90, 62, 152
Sophmore = 184, 16, 200
Total = 274, 78, 352
Step-by-step explanation:
274 - 184 = 90
90 + 62 = 152
352 - 152 = 200
200 - 184 = 16
16 + 62 = 78
Answer:
B
Step-by-step explanation:
Answer:
You divide by - 1
Step-by-step explanation:
-x divided by - 1 is x
5 divided by - 1 is - 5
x > - 5
Calculate those problems in photomath or mathaway it will help promise.