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4 years ago

Assume that y varies inversely with x if y = 4 when x = 4 find y when x = 2

Mathematics

1 answer:

ANEK [815]4 years ago

3 0

When two variables varies inversely with each other, their product is always constant.

Since y = 4 when x = 4, their constant product is 16.

So when x = 2, y = 8.

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I need help with these 2

VashaNatasha [74]

For the first one you need to do
x+2+x+2+2x+4+2x+4
=6x+12

When doing this kind of problem you should use FOIL
First, Outer, Inner, Last
(x+2)(2x+4)
First- x•2x= 2x^2
Outer- x•4= 4x
Inner- 2•2x= 4x
Last- 2•4= 8

Combined you have
=2x^2+8x+8

5 0

3 years ago

What is ....

Airida [17]

5ft 4in= 64 inches
3yd 5in= 113 inches
5yd 2ft= 204 inches/ 17 feet
9ft 6in= 114 inches

5 0

3 years ago

Find the distance between the points H and C. A) 0 B) 2 C) 4 D) 8

RSB [31]

Answer:

Step-by-step explanation:

1.b

2.c

3.d

4.g

6 0

3 years ago

Pleaseeee help meeeeeee

Maslowich

That my dear your answer would be 16 degrees hope this helped

5 0

3 years ago

What are the values of mode and median in the following set of numbers? 1,3,3,6,6,5,4,3,1,1,2 Mode: 1, 2, Median: 2 Mode: 1,3, M

AURORKA [14]

<h3>given:</h3>

$1 \: 3 \: 3 \: 6 \: 6 \: 5 \: 4 \: 3 \: 1 \: 1 \: 2$

the mode and median of the given numbers set.

<h3>solution:</h3><h3>mode:</h3>

the most frequently occurred number.

$mode = 1 \: and \: 3$

<h3>median:</h3>

first arrange all the numbers in either decending or ascending order, then find the number in the middle.

$1 \: 1 \: 1 \: 2 \: 3 \: 3 \: 3 \: 4 \: 5 \: 6 \: 6$

$median = 3$

hence, the median of the following data set is 3 and the mode is 1 and 3

8 0

2 years ago

Assume that y varies inversely with x if y = 4 when x = 4 find y when x = 2​

Assume that y varies inversely with x if y = 4 when x = 4 find y when x = 2