Let x represents the number of dvds sold per day:
To complete the probability distribution table, you need to add all the probabilities given and deduct that to 1 so that you can get the probability of 5-9, applying what I have said:Probability of 5-9:= 1 - (0.1875+0.4375+0.1250) = 1 – 0.75= 0.2500
But the question is not asking for the probability of 5-9, but 5 or more. So deduct the .1875 to 1 since .1875 only represents 0-4.P(X>= 5) = 1 - 0.1875 = 0.8125
Answer:
The minumum numeric grade you have to earn to obtain an A is 81.29.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The professor curves the grades so that the top 8% of students will receive an A. What is the minumum numeric grade you have to earn to obtain an A?
The minimum numeric value is the value of X when Z has a pvalue of 1-0.08 = 0.92. So it is X when Z = 1.405.
So




The minumum numeric grade you have to earn to obtain an A is 81.29.
Answer:
8n + 5 = 69
And that number is 8, because 8•8+5=69
Step-by-step explanation:
"eight times a number and five is sixty-nine" in this statement the words "a number" is the number we dont know and so we use a variable for it. I put n, but you could have used x or a or any variable. The "and five" indicates adding. The "is" indicates equals.
Answer: C. 2,787.64 yd.³
Step-by-step explanation:
Diameter = 22 Yards
Radius = 11 Yards (Diameter/2)
Height = 22 Yards
V = 1/3Bh
V = 1/3π(11 yd)²×(22yd)
V = 1/3π(121 yd)×(22yd)
V = 1/1π(121 yd)×(7.33yd)
V = 886.93π yd.³
V ≈ 2,787.64 yd³