Answer:
0.29
Step-by-step explanation:
Given :
n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4
P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01
The expected number of defect in a shipment can be obtained using the expected value formula :
Expected value, E(X) = Σx*p(x)
Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)
E(X) = 0.29
Hence, the expected number of defect in shipment is 0.29
Hi there!
Im so sorry for wasting an answer on this but Im stuck on this one too and will inform you on when I get the answer!
:) ttyl
Answer:
L and P because they’re degrees equal 180
Step-by-step explanation:
The product is multiplication
6*4296=25776
hope this helps!
