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Ray Of Light [21]
3 years ago
8

How much dirt is in a hole that is 36 inches long, 2 yards wide , and 6 feet deep ?

Mathematics
1 answer:
ra1l [238]3 years ago
3 0

Answer:

96 feet cubed

Step-by-step explanation:

I think it's right. 36 inches to feet, 2 yards to feet, 6 feet

3*6*6

96 I think

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The graph of which function has a minimum located at (4, –3)?
valentinak56 [21]

Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^{2}+k

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case A is not the solution

case B) we have

f(x)=-2x^{2}+16x-35

This case is a vertical parabola open downward (the vertex is a maximum)

The vertex is the point (4,-3) <u>but is not a minimum</u>

see the attached figure

therefore

case B is not the solution

case C) we have

f(x)=x^{2}-4x+5

Convert into vertex form

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f(x)-5=x^{2}-4x

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-5+4=(x^{2}-4x+4)

f(x)-1=(x^{2}-4x+4)

Rewrite as perfect squares

f(x)-1=(x-2)^{2}

f(x)=(x-2)^{2}+1 --------> vertex form

The vertex is the point (2,1)

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case C is not the solution

case D) we have

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Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-35=2x^{2}-16x

Factor the leading coefficient

f(x)-35=2(x^{2}-8x)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-35+32=2(x^{2}-8x+16)

f(x)-3=2(x^{2}-8x+16)

Rewrite as perfect squares

f(x)-3=2(x-4)^{2}

f(x)=2(x-4)^{2}+3 --------> vertex form

The vertex is the point (4,3)

therefore

case D is not the solution

The answer to the question will be the function

f(x)=2x^{2}-16x+29

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