Given :
Median salary of engineer , E = $55,000 .
Median salary of computer engineer , C = $52,000 .
To Find :
The total cost for a business to employ two engineers and three programmers for 1 year .
Solution :
Now , cost of paying two engineers .
Also , cost of paying three programmers .
Therefore , total cost for 1 year is 
.
Hence , this is the required solution .
Answer:
Step-by-step explanation:
So the down payment is: 15% of $250,000 = 0.15 x 250000 = 37,500
The Closing costs = 3% of $250,000 = 0.03 x 250000 = 7,500
Monthly payments = $282,089.89
Total cost of the house is 37,500 + 7,500 + 282,089.89 = $327,089.89
Option A.
Answer:
211,782
Step-by-step explanation:
Esta pregunta es muy fácil porque Los espectadores en total que presenciaron los seis partidos en total es la suma de ambos.
125,429 en uno lado y 86,353 en uno lado. Y eso es igual
125,429 + 86,353 = 211,782
Los espectadores en total que presenciaron los seis partidos en total es 211,782
<h3>Given</h3>
- a cone of height 0.4 m and diameter 0.3 m
- filling at the rate 0.004 m³/s
- fill height of 0.2 m at the time of interest
<h3>Find</h3>
- the rate of change of fill height at the time of interest
<h3>Solution</h3>
The cone is filled to half its depth at the time of interest, so the surface area of the filled portion will be (1/2)² times the surface area of the top of the cone. The filled portion has an area of
... A = (1/4)(π/4)d² = (π/16)(0.3 m)² = 0.09π/16 m²
This area multiplied by the rate of change of fill height (dh/dt) will give the rate of change of volume.
... (0.09π/16 m²)×dh/dt = dV/dt = 0.004 m³/s
Dividing by the coefficient of dh/dt, we get
... dh/dt = 0.004·16/(0.09π) m/s
... dh/dt = 32/(45π) m/s ≈ 0.22635 m/s
_____
You can also write an equation for the filled volume in terms of the filled height, then differentiate and solve for dh/dt. When you do, you find the relation between rates of change of height and area are as described above. We have taken a "shortcut" based on the knowledge gained from solving it this way. (No arithmetic operations are saved. We only avoid the process of taking the derivative.)
Note that the cone dimensions mean the radius is 3/8 of the height.
V = (1/3)πr²h = (1/3)π(3/8·h)²·h = 3π/64·h³
dV/dt = 9π/64·h²·dh/dt
.004 = 9π/64·0.2²·dh/dt . . . substitute the given values
dh/dt = .004·64/(.04·9·π) = 32/(45π)
