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Vlada [557]
3 years ago
15

Somebody please help

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0
What do u need help with 

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Cs.
kykrilka [37]

Answer:

Length of rectangle = 16 cm

Width of rectangle = 4 cm

Step-by-step explanation:

Given:

Area of rectangle = 64 cm²

Find:

Length and width

Computation:

Assume;

Length of rectangle = a

So,

Width of rectangle = a -12

Area of rectangle = l x b

So,

a(a-12) = 64

a² - 12a - 64 = 0

a² - (16-4)a - 64 = 0

a² - 16a+ 4a - 64 = 0

a (a-16) + 4(a-16)= 0

(a-16)(a+4) = 0

a= 16 , a = -4

So,

Length of rectangle = 16 cm

Width of rectangle = a -12

Width of rectangle = 16 -12

Width of rectangle = 4 cm

3 0
3 years ago
Cody wants to attend the fall festival at school
iVinArrow [24]

Answer:

Then let Cody attend the fall festival!!

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
7(2p+3)-8=6p+29<br> Please some help me solve this equation with steps.
stepan [7]
So,

First, I'd like to note that it is required to show work.  You shouldn't need to ask for steps.

7(2p + 3) - 8 = 6p + 29

Distribute
14p + 21 - 8 = 6p + 29

Collect Like Terms
14p + 13 = 6p + 29

Subtract 6p from both sides
8p + 13 = 29

Subtract 13 from both sides
8p = 16

Divide both sides by 8
p = 2

Check
7(2(2) + 3) - 8 = 6(2) + 29

Simplify inside the parentheses first.
7(4 + 3) - 8 = 6(2) +  29
7(7) - 8 = 6(2) + 29

Now, distribute.
49 - 8 = 12 + 29

Collect Like Terms
41 = 41 This checks.

S = { 2 }
4 0
3 years ago
Read 2 more answers
Please Help Me!!!!
ra1l [238]
2. WXZ=YXZ
3.  Reflexive property of equality
(if they are angles)-
4. WXZ=YXZ ~~Reason- Congruent angles have equal number of degrees
(if they are triangles-more likely judging by the problem)-
4. Triangle WXZ=YXZ ~ Reason- SAS Congruence Postulate
5 0
3 years ago
Anyone have the answer for this
sergiy2304 [10]

\huge\bold{Given:}

Length of the base = 16 km.

Length of the hypotenuse = 34 km. \huge\bold{To\:find:}

✎ The length of the missing leg ''a".

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

The length of the missing leg "a" is\boxed{30\:km}.

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

Using Pythagoras theorem, we have

({perpendicular})^{2}  +  ({base})^{2}  =  ({hypotenuse})^{2}  \\ ⇢ {a}^{2}  +  ({16 \: km})^{2}  =  ({34 \: km})^{2}  \\ ⇢ {a}^{2}   + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 1156 \:  {km}^{2}  - 256 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 900 \:  {km}^{2}  \\ ⇢a \:  =  \sqrt{900  \: {km}^{2} }  \\ ⇢a =  \sqrt{30 \times 30 \:  {km}^{2} }  \\ ⇢a = 30 \: km

\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}

\huge\bold{To\:verify :}

( {30 \: km})^{2}  +  ({16 \: km})^{2}  =(  {34 \: km})^{2}  \\ ⇝900 \:  {km}^{2}  + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\⇝1156 \:  {km}^{2}  = 1156 \:  {km}^{2}   \\ ⇝L.H.S.=R. H. S

Hence verified. ✔

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

7 0
2 years ago
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