Somebody please help

2 factor of 28 added up to 9

kaheart [24]

I think its 14 because in order to get to 28 but 2 you count 14 times saying 2×14

5 0

3 years ago

Please answer fully/////////////

Eva8 [605]

Answer:

Step-by-step explanation:

Tear this apart piece by piece

15 - 8 = 7

7 * 3 = 21

11 + 21 = 32

Now so far this much is correct. The problem is the next sign. Is it add or is it divide. The only way to resolve it is to do it both ways.

Add 4

32 + 4 = 36

Divide 4

32 / 4 = 8 1/4 = 8

3 0

2 years ago

Read 2 more answers

Write a word problem that can be solved using the equation 5x = 3x + 20

hram777 [196]

John has x amount of dogs. Solve for x to find how many dogs john has.

8 0

3 years ago

Help me plz, i’d love u forever

Sergio039 [100]

1. We know that 1 feet = 12 inches

let x be a number of inches, which when added to 18 inches will give 7 feet

18 inches + x inches = 7 feet

18 inches + x inches = 84 inches [1 feet = 12 inches]

x inches = 84 inches - 18 inches

x inches = 66 inches

2. We know that 1 mile = 1760 yards

let x be the number of yards, when added to 2000 yards will be equal to 2 miles

2000 yards + x yards = 2 miles

2000 yards + x yards = 3520 yards

x yards = 1520 yards

3. We know that 1 feet = 12 inches

Number of feet = Given number of inches / 12

Number of feet = 108 / 12

Number of feet = 9 ft.

4. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 8800 feet. will be equal to 8 miles

8800 feet + x feet = 8 miles

8800 feet + x feet = 42240 feet [1 mile = 5280 feet]

x feet = 42240 - 8800

x feet = 33440 ft.

5. We know that 12 inches = 1 feet

let x be the number of inches, when added to 37 inches, will be equal to 5 feet

37 inches + x inches = 5 feet

37 inches + x inches = 60 inches [12 inches = 1 feet]

x inches = 23 inches

6. We know that 1 yard = 3 feet

So, (number of yards)*3 = (number of feet)

Number of yards = number of feet / 3

Number of yards = 73 / 3 = 24.33 yards

7. We know that 1 yard = 3 feet

let x be the number of feet added to 15 feet to make 9 yards

15 feet + x feet = 9 yards

15 feet + x feet = 27 feet [1 yard = 3 feet]

x feet = 12 ft

8. We know that 1 mile = 1760 yards

let x be the number of yards remaining to reach 4 miles

3000 yards + x yards = 4 miles

3000 yards + x yards = 7040

x yards = 4040 yards

9. We know that 1 yard = 3 feet

So, number of yards * 3 = number of feet

replacing the values:

number of yards*3 = 114

number of yards = 114/3

number of yards = 38 yards

10. We know that 1 mile = 5280 feet

let x be the number of feet that must be added to 9000 feet to make 3 miles

x feet + 9000 feet = 3 miles

x feet + 9000 feet = 15840 feet

x ft = 6840 ft

11. We know that 12 inches = 1 feet

let x be the number of inches that must be added to 46 inches to get a length of 9 feet

46 inches + x inches = 9 feet

46 inches + x inches = 108 inches

x inches = 108 - 46 inches

x inches = 62 inches

12. We know that 1 mile = 1760 yards

let x be the number of yards that must be added to 3500 yards to make 2 miles

3500 yards + x yards = 2 miles

3500 yards + x yards = 3520 yards

x = 20 yards

13. We know that 1 ft = 12 inches

So, number of feet * 12 = number of inches

number of feet = number of inches / 12

number of feet in 252 inches

Number of feet = 252/12

Number of feet = 21 ft

14. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 6500 feet, will be equal to 2 miles

x ft + 6500 ft = 2 miles

x ft + 6500 ft = 10560 ft

x ft = 4060 ft

15. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 4500 feet, will be equal to 1 mile

x ft + 4500 ft = 1 mile

x ft + 4500 ft = 5280 ft

x ft = 780 ft

3 0

3 years ago

Given: ∆ABC –iso. ∆, m∠BAC = 120°

lidiya [134]

Answer: $P\triangle ADH = (a+b+\sqrt{a^2+b^2} )$ unit

Step-by-step explanation:

Since Here Δ ABC is a isosceles triangle.

Also, $AH\perp BC$ and $HD\perp AC$

Thus, ∠ ADH = 90°

That is, Δ ADH is the right angle triangle.

In which, AD = a unit and HD = b unit

And, By the definition of Pythagoras theorem,

$AH^2 = HD^2 + AD^2$

⇒ $AH^2 = a^2 +b^2$

⇒ $AH = \sqrt{a^2+b^2}$

Since, the perimeter of a triangle = sum of the all sides of the triangle.

Therefore, perimeter of ΔADH = AD + DH + AH

= $a + b + \sqrt{a^2+b^2}$ unit

4 0

3 years ago