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Advocard [28]
3 years ago
14

Help help help help help

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

m(∠y) = 64°

Step-by-step explanation:

From the figure attached,

m(∠e) = 90°

m(∠b) + 67° = 180° [Linear pair of angles]

m(∠b) = 180 - 67

          = 113°

m(∠c) + 75° = 180°  [Linear pair of angles]

m(∠c) = 105°

m(∠a) = m(∠d)

By the property of a polygon,

Sum of the interior angles of a polygon is given by,

Sum of interior angles = (n - 2) × 180°

Here, n = number of sides of the polygon

For n = 5,

Sum of interior angles = (5 - 2)×180°

                                     = 540°

m(∠a) + m(∠b) + m(∠c) + m(∠d) + m(e) = 540°

2m(∠d) + 113° + 105° + 90° = 540°

2m(∠d) + 308 = 540°

2m(∠d) = 540 - 308

m(∠d) = 116°

m(∠d) + m(∠y) = 180°

m(∠y) + 116° = 180° [Linear pair of angles]

m(∠y) = 64°

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Step-by-step explanation:

100%

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The area of a rectangle is expressed as (12m+18) square feet. If the width of the rectangle is 6 feet, choose an expression to r
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4 0
3 years ago
A health statistics agency in a certain country tracks the number of adults who have health insurance. Suppose according to the
Nana76 [90]

Answer:

a) There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

Step-by-step explanation:

We have these following percentages:

5.3% of those under the age of 18, 12.6% of those ages 18–64, and 1.3% of those 65 and older do not have health insurance.

22.6% of people in the county are under age 18, and 62.1% are ages 18–64.

(a) What is the probability that a randomly selected person in this country is 65 or older?

22.6% are under 18

62.10% are 18-64

The rest are above 65

So

100% - (22.6% + 62.10%) = 15.3%

There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, what is the probability that the person is 65 or older?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So, what is the probability that a person is 65 and older, given that the person is uninsured.

P(B) is the probability that a person is 65 and older. From a), we have that P(B) = 0.153

P(A/B) is the probability is uninsured, given that that person is 65 and older. So P(A/B) = 0.013

P(A) is the probability that a person is uninsured. That is the sum of 5.3% of 22.6%, 12.6% of 62.1% and 1.3% of 15.3%. So:

P(A) = 0.053*(0.226) + 0.126*(0.621) + 0.013*(0.153) = 0.0922

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.153*0.013}{0.0922} = 0.022

Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

6 0
3 years ago
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5 0
4 years ago
Engineering students at riverside college last year received, on. Average, $11,070 in scholarships and grant money. This year, t
Sveta_85 [38]

Answer:the average this year is $13284

Step-by-step explanation:

Engineering students at riverside college last year received, on. Average, $11,070 in scholarships and grant money. This year, the average is 20% higher. The value of the increase would be

20/100 × 11070 = 0.2 × 11070 = $2214

Therefore, the average this year would be the sum of the average last year and the value of the increase. It becomes

11070 + 2214 = $13284

4 0
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