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sergiy2304 [10]
3 years ago
12

What is the area of the yellow square?The area of the green square is 9 ft2. The area of the red square is 16 ft2.

Mathematics
2 answers:
eduard3 years ago
8 0

Answer:

Okay if you want the answer quick and fast its     <u>A). 25ft²</u>



joja [24]3 years ago
7 0
Well abnormal square would have four equal sides therefore for the firemen square since it's 9 ft^2 then u square root it and u get 3 that means each side in that green square is 3 now for the red one with 16ft^2 it would be the same consept u would square root 16 which u would get 4 now the two legs are 3 and four now u are missing the hypotenuse at c thus u use pythogerom theorom I don't know how to spell it so don't complain! You would do 3^2+4^2=c^2 which would result to 9+16=c^2. From there u would add and you would get 25 =c^2 and the reverse property of square would be square root it's that radical symbol if u remember so radical 25=5. We are still not finished we have to find the area and since we are working with normal squares where each sides ar eewual then u do 5*5 u get 25!
Now don't forget to write ft2 because then u will get it wrong
And don't be a lazy bum and try rechecking my work because I did it all in my head ok it's 12 o'clock a.m.
Peace
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Answer:

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Step-by-step explanation:

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Evaluate the statement “W must be at –3.”
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E Exponents (ie Powers and Square Roots, etc.)

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area in white

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8 0
4 years ago
Please Help! I'm stuck on this question. Show all work!
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Add all the displacement vectors together, then find the magnitude of this vector sum.

\vec r_1=(72\,\mathrm{km})(\cos60^\circ\,\vec\imath+\sin60^\circ\,\vec\jmath)

\vec r_2=(48\,\mathrm{km})(\cos270^\circ\,\vec\imath+\sin270^\circ\,\vec\jmath)

\vec r_3=(100\,\mathrm{km})(\cos150^\circ\,\vec\imath+\sin150^\circ\,vec\jmath)

Summing these vectors gives the resultant displacement

\vec r=\vec r_1+\vec r_2+\vec r_3\approx(-50.6\,\vec\imath+64.4\,\vec\jmath)\,\mathrm{km}

and we have

\|\vec r\|=\sqrt{(-50.6)^2+64.4^2}\,\mathrm{km}\approx\boxed{81.9\,\mathrm{km}}

so the plane ends up about 81.9 km away from its starting position.

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4 years ago
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