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Svetach [21]
3 years ago
14

How would you write an equation of the line with the points (-2,4) (4,1)

Mathematics
1 answer:
Elena L [17]3 years ago
5 0
There are several eqaiton types

1. point slope
passes through (x1,y1) and has a slope of m
y-y1=m(x-x1)

2. slope intercept
y=mx+b
m=slope
b=y intercept

3. standard form
ax+by=c or ax+by-c=0
where a, b, and c are integers and a is usually positive


so


first find the slope

slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
slope between (-2,4) and (4,1) is (1-4)/(4-(-2))=(-3)/(4+2)=-3/6=-1/2

use point slope
using point (4,1)
y-1=-1/2(x-4)

now let's do slope intercept
solve for y
y-1=-1/2(x-4)
y-1=-1/2x+2
y=-1/2x+3 is slope intercept

now standard form
times both sides by 2
2y=-x+6
add x both sides
x+2y=6 is standard form



so

possible equations are
y-1=\frac{-1}{2}(x-4)
y-4=\frac{-1}{2}(x+2)
y=\frac{-1}{2}x+3
x+2y=6
x+2y-6=0
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The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

\hat y=\alpha +\hat \beta x

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope (\hat \beta ) is:

Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

\hat Y=3.584756+0.090953 X

The summary of the regression analysis is:

Predictor          Coefficient             SE             t-stat            p-value

Constant             3.584756          0.078183       45.85075      5.66 x 10⁻¹¹

Entering GPA   0.090953          0.022162        4.103932       0.003419

The regression coefficient and standard error are:

\hat \beta = 0.090953\\SE (\hat \beta)=0.022162

The critical value of <em>t</em>  for 95% confidence level and 8 degrees of freedom is:

t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306

Compute the 95% confidence interval for (\hat \beta ) as follows:

CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0
3 years ago
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