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Svetach [21]
3 years ago
14

How would you write an equation of the line with the points (-2,4) (4,1)

Mathematics
1 answer:
Elena L [17]3 years ago
5 0
There are several eqaiton types

1. point slope
passes through (x1,y1) and has a slope of m
y-y1=m(x-x1)

2. slope intercept
y=mx+b
m=slope
b=y intercept

3. standard form
ax+by=c or ax+by-c=0
where a, b, and c are integers and a is usually positive


so


first find the slope

slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
slope between (-2,4) and (4,1) is (1-4)/(4-(-2))=(-3)/(4+2)=-3/6=-1/2

use point slope
using point (4,1)
y-1=-1/2(x-4)

now let's do slope intercept
solve for y
y-1=-1/2(x-4)
y-1=-1/2x+2
y=-1/2x+3 is slope intercept

now standard form
times both sides by 2
2y=-x+6
add x both sides
x+2y=6 is standard form



so

possible equations are
y-1=\frac{-1}{2}(x-4)
y-4=\frac{-1}{2}(x+2)
y=\frac{-1}{2}x+3
x+2y=6
x+2y-6=0
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astra-53 [7]

The answers to the given addition operations are

7) 6 Hundredths add to 4 tenths add to 6 ones is equal to 6.46

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<h3>Addition operation </h3>

From the question, we are to add the given numbers

7. 6 Hundredths add to 4 tenths add to 6 ones is equal to

6 Hundredths = 0.06

4 tenths = 0.4

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Thus, we get

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8. 82 Hundredths add to 9 tenths add to 4 tens is equal to

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0.82 + 0.9 + 40 = 41.72

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8) 82 Hundredths add to 9 tenths add to 4 tens is equal to 41.72

Learn more on Addition operation here: brainly.com/question/4248979

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Digiron [165]
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A rectangle's area is given by the expression 6n2-n+
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Answer:

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Step-by-step explanation:

Rectangle area  = A = 6 n^2  - n + 9

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