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kherson [118]
3 years ago
9

The goals against average (A) for a professional hockey goalie is determined using the formula A = 60 a equals 60 left-parenthes

is StartFraction g Over t EndFraction right-parenthesis.. In the formula, g represents the number of goals scored against the goalie and t represents the time played, in minutes. Which is an equivalent equation solved for g? StartFraction A t Over 60 EndFraction equals g.= g StartFraction A Over 60 t EndFraction equals g. = g StartFraction 60 A Over t EndFraction equals g. = g 60At = g
Mathematics
2 answers:
dangina [55]3 years ago
6 0

Answer:

Option 1 - \frac{At}{60}=g

It's A

Step-by-step explanation:

Marina CMI [18]3 years ago
4 0

Answer:

Option 1 - \frac{At}{60}=g

Step-by-step explanation:

Given : The goals against average (A) for a professional hockey goalie is determined using the formula A=60(\frac{g}{t} ). In the formula, g represents the number of goals scored against the goalie and t represents the time played, in minutes.

To find : Which is an equivalent equation solved for g?

Solution :

Solve the formula in terms of g,

A=60(\frac{g}{t})

Multiply both side by t,

At=60g

Divide both side by 60,

\frac{At}{60}=\frac{60g}{60}

\frac{At}{60}=g

Therefore, option 1 is correct.

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En un pueblo hay tres iglesias cuyas campanas tocan cada 15 minutos, cada 20 minutos y cada 35 minutos. Suponiendo que en este i
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Answer:

420 minutos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encontramos los múltiplos de 15, 20 y 35

Múltiplos de 15:

15, 30, 45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195, 210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375, 390, 405, 420, 435, 450

Múltiplos de 20:

20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240, 260, 280, 300, 320, 340, 360, 380, 400, 420, 440, 460

Múltiplos de 35:

35, 70, 105, 140, 175, 210, 245, 280, 315, 350, 385, 420, 455, 490

Por lo tanto,

MCM (15, 20, 35) = 420

El primer múltiplo común es el mínimo común múltiplo.

Por tanto, el tiempo en el que las 3 campanas de la iglesia volverán a coincidir = 420 minutos

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