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vekshin1
3 years ago
13

Is x+1 a factor? Why or why not?

Mathematics
1 answer:
castortr0y [4]3 years ago
8 0
No it is not a factor Mark me as Brainliest
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What property proves equivalency?
Olenka [21]

Answer:

i think its c.distributive

8 0
3 years ago
Bring the fraction a/a−4 to a denominator of 16−a^2<br><br> really do appreciate this thx
RSB [31]

Answer:

-a(a+4)/(16 - a²)

Step-by-step explanation:

            a/(a - 4)                  Multiply by (a + 4)/(a + 4)

= a(a + 4)/[(a – 4)(a + 4)]     Multiply the denominatorator terms

= a(a + 4)/(a² - 16)               Multiply by -1/(-1)

= -a(a+4)/(-a² + 16)              Reorder terms in denominator

= -a(a+4)/(16 - a²)

5 0
3 years ago
Can someone help me with this right answer only and please explain it too
sineoko [7]

Answer:

g(6) = 71

f(11) = 62

Step-by-step explanation:

Let's solve g(6) first

Plug 6 into x

g(6) = 2(6)^2 - 1

g(6) = 2(36) - 1

g(6) = 72 - 1

g(6) = 71

Now let's solve f(11)

f(11) = 5(11) + 7

f(11) = 55 + 7

f(11) = 62

<em>Thus, out answers are 71 and 62 respectively</em>

5 0
3 years ago
NEED HELP!!! please:)
Dahasolnce [82]
No, Jonah is not correct. The answer is shown in the picture.

8 0
3 years ago
You want to place a towel bar that is 24 1/4 centimeters long in the center of a door that is 70 1/3 centimeters wide. How far s
Aleksandr [31]

Answer:

The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

Step-by-step explanation:

Given:

Length of the towel bar = 24\frac14\ cm

Now given length is in mixed fraction we will convert in fraction.

To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.

24\frac14\ cm can be Rewritten as \frac{97}{4}\ cm

Length of the towel bar =  \frac{97}{4}\ cm

Length of the door = 70 \frac13\ cm

70 \frac13\ cm can be Rewritten as \frac{211}{3}\ cm

Length of the door = \frac{211}{3}\ cm

We need to find the distance bar should be place at from each edge of the door.

Solution:

Let the distance of bar from each edge of the door be 'x'.

 So as we placed the towel bar in the center of the door it divides into two i.e. '2x'

Now we can say that;

\frac{97}{4}+2x=\frac{211}{3}\\\\2x=\frac{211}{3}-\frac{97}{4}

Now we will take LCM to make the denominators common we get;

2x=\frac{211\times4}{3\times4}-\frac{97\times3}{4\times3}\\\\\\2x= \frac{844}{12}+\frac{281}{12}

Now denominators are common so we will solve the numerators.

2x =\frac{844-291}{12}\\\\2x=\frac{553}{12}\\\\x=\frac{553}{12\times2} =\frac{553}{24}

Or x=23\frac{1}{24}\ cm

Hence The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

8 0
3 years ago
Read 2 more answers
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