12 4/5 can be changed as 64/5 so there are 64 1/5ths
Answer:
a =
Step-by-step explanation:
Given:
f(x) = log(x)
and,
f(kaa) = kf(a)
now applying the given function, we get
⇒ log(kaa) = k × log(a)
or
⇒ log(ka²) = k × log(a)
Now, we know the property of the log function that
log(AB) = log(A) + log(B)
and,
log(Aᵇ) = b × log(A)
Thus,
⇒ log(k) + log(a²) = k × log(a) (using log(AB) = log(A) + log(B) )
or
⇒ log(k) + 2log(a) = k × log(a) (using log(Aᵇ) = b × log(A) )
or
⇒ k × log(a) - 2log(a) = log(k)
or
⇒ log(a) × (k - 2) = log(k)
or
⇒ log(a) = (k - 2)⁻¹ × log(k)
or
⇒ log(a) = (using log(Aᵇ) = b × log(A) )
taking anti-log both sides
⇒ a =
There are 3 repeating digits in 0.536 because there are 3 numbers behind the decimal
Here is the work:
(13x - 5x) + 12 - 2y = 6
(8x) + 12 - 2y = 6
-2y = -8x - 12 + 6
-2y = -8x - 6
y = 4x + 3