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zmey [24]
2 years ago
5

Martin is two years older than Reese, and the same age as Lee. If Lee is 12, how old is Reese?

Mathematics
2 answers:
VLD [36.1K]2 years ago
5 0

Answer: Reese is 10 years old.

Step-by-step explanation:

Let be "m" the age of Martin and "r" tthe age of Reese and "l" the age of Lee.

Based on the information provided in the exercise, you can set up the following equations:

m=r+2     [Equation 1]

m=l         [Equation 2]

l=12        [Equation 3]

Therefore, since:

m=l

You know that:

m=12

Now you must substitute the value of "m" into [Equation 1]:

12=r+2

Finally, you must solve for "r" in order to find its value. This is:

12-2=r\\\\r=10

joja [24]2 years ago
4 0

Answer:

Reese has 10 years old.

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If the m∠SRW = 85°, what are the measures of ∠VRU and ∠URW?<br><br> m∠VRU = °<br><br> m∠URW = °
alina1380 [7]

Answer:

see explanation

Step-by-step explanation:

∠TRV = ∠SRW ( vertical angles ), hence

2x + 15 = 85 ( subtract 15 from both sides )

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Hence

∠VRU = 2x + 10 = ( 2 × 35) + 10 = 70 + 10 = 80°

and

∠URW + ∠VRU + ∠SRW = 180 ( sum of angles in a straight line ), thus

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2 years ago
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Suppose you have 30CD's. You know that you have 11 more CD's than your friend. Write and solve an equation to find the number of
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Step-by-step explanation:


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3 years ago
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​write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)
Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

log_{4 }6ab

This can be written as

log_{4 }6 \times a \times b

From one of the rules of logarithm, we have that

log_{x }yz= log_{x }y + log_{x }z

Thus,

log_{4 }6 \times a \times b  becomes

log_{4 }6 + log_{4 }a + log_{4 }b

This can be further simplified into

log_{4 }3 \times 2 + log_{4 }a + log_{4 }b

log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b

If desired, this can be further simplified into

log_{4 }3 + log_{2^{2}  }2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b

\frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Learn more on Simplifying logarithms here: brainly.com/question/17851187

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A easy question help.
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