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2 years ago

What is the domain of the continuous quadratic function y = 3x^2+1 ?

1 answer:

6 0

Domain is what can be put into the function to make it work

Considering that there are no numbers that 3x^2 cannot handle then the domain is all real numbers

You might be interested in

Is 81 a multiple of 3? Explain, Is 46 a multiple of 4, Explain, Is 55 a multiple of 7? Explain Is 72 a multiple of 9 explain, Is

ra1l [238]

3x27=81 so 81 is a multiple of 3

there is no integer x for which 4x=46 so 46 is not a multiple of 4

there is no integer x for which 7x=55 so 55 is not a multiple of 7

72 = 8*9 so 72 is a multiple of 9

there is no integer x for which 6x=45 hence 45 is not a multiple of 6

6 0

3 years ago

What is the length of the hypotenuse, x, if (20,21,x) is a Pythagorean triple?

Sophie [7]

Answer:

Step-by-step explanation:

$(20,21,x) \\Pythagoras -Theorem =\\a^2+b^2 = c^2\\\\20^2 + 21^2 = x^2\\400 + 441 = x^2\\841 = x^2\\Square -root-both-sides\\\sqrt{841} = \sqrt{x^2} \\29 = x\\\\x = 29$

6 0

2 years ago

Read 2 more answers

All perfect numbers from 20 to 30

lana [24]

Answer:

There is only one perfect number between 20 to 30 which is 28.

<h3>Explanation:</h3>

The number 28 is a perfect number because its factors are 1, 2, 4, 7, 14 and 28.

7 0

2 years ago

Can you guys help me with integers it these four problems for the first image do 18 and 19 for the second it’s 7 and 11 please h

xxMikexx [17]

Answer:

18. 20,000.

19. 0

7. 1

11. 101

Step-by-step explanation:

18. I think is stays the same, because an integer is a number that is not a fraction. So still 20,000.

19. Sea level is at zero altitude. So answer is 0.

7. |17-16| = |1| = 1. The lines around it are called absolute value signs and mean to make the answer positive.

11. |-101| = 101. As said before the lines mean to make the inside part positive.

6 0

3 years ago

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%

bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400 at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

$\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}$

a = $800

The amount of money invested at 6% = a = 800

The amount of money invested at 4 % = 3a = 3(800) = 2400

So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

4 0

2 years ago