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BARSIC [14]
3 years ago
12

the area of the retangler piece of foil is 11 1/4 square inches its length is 4 1/2 inches what is the width of the foil?

Mathematics
2 answers:
quester [9]3 years ago
7 0

Answer:

The width of the foil = w = 2.5 inches

Step-by-step explanation:

We know that the Area of a rectangular piece:

A=wl

Here:

  • 'w' is the width
  • 'l' is the length

Given that area of the rectangular piece of foil:

Area = A = 11 1/4 square inches

               = 45/4 square inches

               = 11.25 square inches  

                                                                         

Length = l = 4 1/2 inches

                 = 9/2 inches

                 = 4.5 inches

Using the Area formula

A=wl

w\:=\:\frac{A}{l}

    =\frac{11.25}{4.5}

    = 2.5 inches

Thus, the width of the foil = w = 2.5 inches

goldfiish [28.3K]3 years ago
4 0

Answer:

Step-by-step explanation:

I think it would be 5

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Answer:

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Step-by-step explanation:

Given

See attachment for class

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Class 66 - 68:

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\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

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Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

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