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Akimi4 [234]
2 years ago
7

Four students in an art class mixed red and blue paint to make purple. The amounts they used are shown in the table. Which stude

nt made a different shade of purple than the other students.
Mathematics
1 answer:
alexira [117]2 years ago
3 0

Based on the mixtures of the four students in the art class, the student with a different shade of purple would be Aiden.

<h3>Why would Aiden's mixture be different?</h3>

In order to solve this question, look at the ratio of red paint to blue paint for all the students:

Alec:

1¹/₃ : ²/₃

2 : 1

Rosa:

2¹/₂ : 1 ¹/ ₄

2  :  1

Aidan:

4¹/₂  : 2

2.25 :  2

Zoe:

5 : 2¹/₂

2 : 1

Notice that Aidan's mixture is the only one that is different and so will have a different shade of purple as a result.

Find out more on ratios at brainly.com/question/2328454.

#SPJ1

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nadya68 [22]
5(6*3) = 5(18) = 90

(5*6)3 = (30)3 = 90

The answer is the same by the associative law.
6 0
2 years ago
Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
3 years ago
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0
3 years ago
Explain how you can tell that 31\33 is in simplest form
Sindrei [870]
Because there is no whole number that you can divide into both the numerator and the denominator to get a proper fraction.
3 0
2 years ago
Read 2 more answers
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Paha777 [63]

Answer: the computer towers will be worth $10521 after 8 years

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^t

Where

A represents the value of the computer towers after t years.

t represents the number of years.

P represents the initial value of the computer towers.

r represents rate of decay.

From the information given,

P = $30900

r = 12.6% = 12.6/100 = 0.126

Therefore, the function that models the value of the computer towers after (t)years from now is

A = 30900(1 - 0.126)^t

A = 30900(0.874)^t

Therefore, when t = 8 years, then

A = 30900(0.874)^8

A = $10521

6 0
3 years ago
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