All categories

3 years ago

3m + 7m - 0.8 < 9.2 someone answer this quick plz

Mathematics

2 answers:

otez555 [7]3 years ago

7 0

Your answer is actually m < 0.8

Simora [160]3 years ago

5 0

If you are solving for m
m <1

You might be interested in

use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

5 0

3 years ago

What is n+ 7over10=-1over10

Karo-lina-s [1.5K]

Answer:

- 4/5

Step-by-step explanation:

Step 1:

n + 7/10 = - 1/10

Step 2:

n = - 1/10 - 7/10

Answer:

n = - 4/5

Hope This Helps :)

8 0

3 years ago

Write the equation for a line in slope-intercept form (y=mx+b) that

dalvyx [7]

Answer:

y = -2x - 1

Step-by-step explanation:

Parallel lines have the same slope, so the slope will also be -2.

Plug this slope and the given point into the equation y = mx + b and solve for b:

y = mx + b

5 = -2(-3) + b

5 = 6 + b

-1 = b

Then, plug this and the slope into the equation:

y = -2x -1 will be the equation

3 0

3 years ago

Read 2 more answers

Helpppppppp asap 89points

Lynna [10]

Answer:

the answer for the first is the second one

and the answer for the second is 9>6

Step-by-step explanation:

9 is greater than (>) six

and when plotted you can see that 9 is to the right of -6

hope i helped!

7 0

2 years ago

Read 2 more answers

Simplify: (2x – 3)2 4x2 + 9 4x2 – 12x + 9 4x2 – 12x + 6 4x2 – 6

Alexxandr [17]

Answer:

$4x^2-12x+9$

Step-by-step explanation:

we have

$(2x-3)^2$

we know that

$(a-b)^2=a^2-2ab+b^2$

In this problem

$a=2x\\b=3$

substitute in the formula

$(2x-3)^2=(2x)^2-2(2x)(3)+(3)^2$

$(2x-3)^2=4x^2-12x+9$

7 0

3 years ago

Read 2 more answers