Answer:
D. 48
Step-by-step explanation:
We don't know the numbers of coupons sent to existing members and to potential members, but we know a relationship between the number.
They sent 5 times as many coupons to potential members as they did to existing members.
Let x = number of coupons sent to existing members.
Then 5x = number of coupons sent to potential members.
The total number of coupons sent was x + 5x = 6x
The total number of coupons sent was 288.
Therefore, 6x must equal 288 giving us an equation with a single variable.
6x = 288
x = 48
Answer: 48
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
384
Step-by-step explanation:
multiply all those numbers together
Step-by-step explanation:
-3-4 -32x=3×8x
-3-4-32x=24x
-6=32x+24x
-6=56x
:. x=-28/3
