Which of the following is a flat surface that extends infinitely, has length and width, but does not have depth?

José plotted points on a coordinate plane to represent the vertices of a rectangle. The first

Tema [17]

Jose's rectangle must have equal and parallel opposite sides

The coordinates of the other points could be C(7,5) and D(7,1)

<h3>How to determine the other points?</h3>

The coordinates are given as;

A = (2,5).

B = (2,1).

To form a rectangle, each of the remaining points must have the same y-coordinates as points A and B.

So, we have:

C = (x,5)

D = (x,1)

Also, the remaining points must have the same x-coordinates.

i.e.

Cx = Dx

From the list of options, we have:

C(7,5) and D(7,1)

Hence, the coordinates of the other points could be C(7,5) and D(7,1)

Read more about rectangles at:

brainly.com/question/12500692

3 0

2 years ago

121 is 55% of what number

Wewaii [24]

Let x be the unknown number
x×55%=121
x=121÷55%
x=220
So 121 is 55% of 220

3 0

3 years ago

Based on the following set of data, which of the statements shown is true?

jarptica [38.1K]

C.) mean > median

Hope this helps chu

8 0

3 years ago

Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra

Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

$x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)$

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize $x^2-\frac13$ as yet another difference of squares:

$x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)$

And if you're working over the field of complex numbers, you can go even further. For instance,

$x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)$

But I think you'd be fine stopping at the first result,

$x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}$

6 0

3 years ago

Jack is placing glass bottles into boxes to recycle. He can fit 12 bottles in each box.

djverab [1.8K]

His estimation is not reasonable because if you can only fit 12 bottles in a box and he has 10 boxes then he could only fit 120 out of the 200 bottles so he is short on boxes

6 0

3 years ago