1. She can travel 18 miles. Subtract 35 - 2 (initial fee) to have 33. divide 33 by 1.75 to get 18.85. To check how much her total would be, use inverse operations. 18.85 * 1.75 = 32.9875. 32.9875 + 2 = 34.9875. It is barely under $35 but still in her budget.
2. 20m * $1.75 = $35. $70 - $35 = $35. Yes, she can cover the fare. Samantha has more than needed. She can afford the taxi fare and still have money left for future use.
Answer: 11 weeks
Step-by-step explanation: 11 x 10 + 10 = $120 and 11 x 6 +54 = $120
Mike has 78 feet of fencing available for his garden, this is the perimeter (P) of the rectangle:
Perimeter: P=78 feet
The formula of Perimeter is:
P=2(W+L), where W is the width and L is the length, then:
P=78→2(W+L)=78
Dividing both sides of the equation by 2:
2(W+L)/2=78/2
W+L=39
If the shape is of a golden rectangle, we know:
L=1.6W
Replacing this above:
W+1.6W=39
Adding similar terms:
2.6W=39
Solving for W
2.6W/2.6=39/2.6
W=15 feet
L=1.6W=1.6(15)→L=24 feet
Answer: T<span>he dimensions of the garden are: Width=15 feet and Length=24 feet. </span>
10x + 5 = 16x - 1
<span>6x = 6 </span>
<span>x = 1 </span>
Answer:
The second answer, and possibly the first answer as also true.
She did run a test that would indicate its an unbalanced dice, but this wasn't tried out with a different person throwing the dice.
Step-by-step explanation:
This is because from the computer generator results we see 11 of the 25 values are estimating at 1/5 when we know dice are 1/6 and more than 1/2 show just under 1/5 which balances this to be 1/6
But there are 9/25 tests that showed values under 10 throws found a 6 in 9/25 events = 1/3 approx out of 1/10 of the throws, and 1/3 is still a higher value than 1/6 of the multiple throws so indicates 100 throws would not be enough to tell as we cannot possibly assume her results are comparable with a computer generator.As the computer generator completed 25 x 100 throws and have just compared only x10 in relation to 1/10 of the events of the generated computer. This showing 9 of the 25 (100) throw events in relation scores 1/3 of the results a 6. The answer is she would need to throw somewhere between 1000 and 3000 to compare to the computers results.
