Answer:
- 11040 m³
- k ≈ 0.33
- V = (1/3)Bh
Step-by-step explanation:
The given relation is ...
V = kBh . . . . . for some base area B, height h, and constant of variation k
We are given length and width of the base so we presume it is a rectangle.
B = l·w = 8·11 = 88 . . . . square meters
The given volume tells us the value of k:
1144 = k(88)(39) . . . . . . cubic meters
1144/3432 = k = 1/3 ≈ 0.33
The value of k is about 0.33.
__
Then the volume of the larger pyramid is ...
V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³
The general relationship is ...
V = 1/3Bh
<h3>Corresponding angles =
angle 1 and angle 5</h3>
They are on the same side of the transversal cut (both to the left of the transversal) and they are both above the two black lines. It might help to make those two black lines to be parallel, though this is optional.
Other pairs of corresponding angles could be:
- angle 2 and angle 6
- angle 3 and angle 7
- angle 4 and angle 8
=======================================================
<h3>Alternate interior angles = angle 3 and angle 5</h3>
They are between the black lines, so they are interior angles. They are on alternate sides of the blue transversal, making them alternate interior angles.
The other pair of alternate interior angles is angle 4 and angle 6.
=======================================================
<h3>Alternate exterior angles = angle 1 and angle 7</h3>
Similar to alternate interior angles, but now we're outside the black lines. The other pair of alternate exterior angles is angle 2 and angle 8
=======================================================
<h3>Same-side interior angles = angle 3 and angle 6</h3>
The other pair of same-side interior angles is angle 4 and angle 5. They are interior angles, and they are on the same side of the transversal.
The answer is J. 1/(x^2-x)
Yes. I think so. Even if there is not intercept the intercept is 0
