Yes. There is sixteen ounces in a pound. At thirty cents an ounce, you can buy a pound for $4.80. That also leaves $.20.
The logarithm of 10 to base 10 is 1
<h3>How to determine the logarithm?</h3>
The given parameters are:
Base = 10
Number = 10
So, the expression is:

As a general rule;

The above means that;
When the base and the number are the same, the logarithm is 1
So, we have:

Hence, the logarithmic value is 1
Read more about logarithm at:
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see the attached figure with the letters
1) find m(x) in the interval A,BA (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100
2) find m(x) in the interval B,CB(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20
3)
find n(x) in the interval A,BA (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x
4) find n(x) in the interval B,CB(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30
5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44
6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72
for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72
<span> h'(x) = 1.44 ------------ > not exist</span>
Answer:
<h2>
John has $15 and Alex has $33</h2>
Step-by-step explanation:
a systems of equations can be made from the information on the problem
x+y=48
x=2y+3
since x= 2y+3 substitute 2y+3 in the firat equation to get:
(2y+3)+y=48 -> 3y+3=48 -> 3y=45 -> y=15
plug in 15 for y in the second equation to solve for x
x+15 =48 --> x=33
Hey there!
1a. Let c=cost of dinner, 5=the # of people, and P=the cost of person
P=C/5
b. <span>P = (1000)/5 </span>
<span>P = 200
</span>
2a. For 1= 19, 2= 38, 57= and so on ( you just multiply the number of season by 19)
b. T= 19n