Hey!~
Log 5 + Log 2 = 1
Hope this helps and have a nice day!
-Lindsey
Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via
<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em> ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>
where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.
P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)
… = P(<em>Z</em> < 0.24)
… ≈ 0.5948
Answer:
E
Step-by-step explanation:
A. x/yx * zy/yx = 2/x
B. x/y + y/z = (xz+y^2)/yz
C. x*z/z*x = 1
D. (x+y)/(y+z) = y(x+1)/y(1+z) = x+1/1+z
E. x/y / z/y = x/y * y/z = x/z
Answer:
B
Step-by-step explanation:
Class and cost per class should be multipled so must be A or B. The amount of money she has should be greater than or equal to her costs or she can't afford it! So B.
