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denpristay [2]
3 years ago
5

which of the following is a qualitative statement that is reasonable based on the data? A The fewest number of cars at home is 0

B Most students have 2 or fewer cars at home C Most students have 3 or more cars at home D The median number of cars at home is 3
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

B

Step-by-step explanation:

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What is the slope intercept equation for this graph someone answer the question pls
disa [49]

Answer:

-2,3

Step-by-step explanation:

7 0
3 years ago
The student body President of a high school claims to know the names of at least 1000 of the 1800 students at the school. To tes
hoa [83]

Answer:

The 99% confidence interval for p in this case is (0.3317, 0.5883).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students.

This means that:

n = 100, \pi = \frac{46}{100} = 0.46

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.46 - 2.575\sqrt{\frac{0.46*0.54}{100}} = 0.3317

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.46 + 2.575\sqrt{\frac{0.46*0.54}{100}} = 0.5883

The 99% confidence interval for p in this case is (0.3317, 0.5883).

4 0
2 years ago
Find the difference in height between the top of a hill 973 feet high and a crack caused by an earthquake 79 feet below sea leve
mart [117]

Answer:

1052 feet

Step-by-step explanation:

973+|-79|=1052

6 0
3 years ago
In this problem,y = 1/(x2 + c)is a one-parameter family of solutions of the first-order DEy' + 2xy2 = 0.Find a solution of the f
trasher [3.6K]

Differentiate the given solution:

y=\dfrac1{x^2+C}\implies y'=-\dfrac{2x}{(x^2+C)^2}

Substitute y and y' into the ODE:

-\dfrac{2x}{(x^2+C)^2}+2x\left(\dfrac1{x^2+C}\right)^2=0

and it's easy to see the left side indeed reduces to 0.

6 0
2 years ago
Un curso esta formado por 12 mujeres y 15 hombres ¿cual es la probabilidad de que las personas en el cargo de presidente y visep
riadik2000 [5.3K]

Answer:

P = (12/27)*(11/26) = 0.188

Step-by-step explanation:

Si todos tienen la misma probabilidad de estar en cargo de presidente y vicepresidente, entonces:

La probabilidad de que una mujer sea presidente, es igual al cociente entre el número de mujeres y el número total de personas:

p = 12/27

Ahora queremos calcular lo mismo para vicepresidente, y el cálculo es exactamente igual, con la diferencia de que en esta situación, ya hay una mujer en el cargo de presidente, entonces hay 11 mujeres que pueden ser vicepresidente, y un total de: (11 + 15 = 26 personas)

Entonces ahora la probabilidad es:

q = 11/26

La probabilidad conjunta (es decir, la probabilidad de que ambos eventos pasen) es igual al producto de las probabilidades individuales.

P = (12/27)*(11/26) = 0.188

4 0
2 years ago
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