A tangent line creates a 90 degree angle with a radius line that touches the tangent Line.
Line BC is a radius that touches the tangent line at point C
The angle created is 90 degrees.
The answer is C. 90 degrees.
Okay, let's see...
The problem is asking for a linear equation most likely in the form of y=mx+b
y is another way to say f(x)
<em>m = slope </em>
<em>b = y intercept </em>
Let's start with the y intercept first.
Y intercept means ' When does the line touch (intercept) the y axis.
In this case, if you look at the graph, the line <em>touches </em>the y axis at -1.
-1 will replaces b
To find the slope we are going to take 2 precise points from the graph.
Lets use <em>(0,-1)</em> and <em>(-6,4) </em>
To find the slope, we're going to use 
4 - (-1) / -6 - 0
Solve, our slope is 5/-6
That is our m
Our final equation is
Divide both sides by -5
Sqrt(x) = 3
We want to isolate x to solve for it. The opposite of a square root is a square, so square both sides.
x = 9
It can't be -9 because the square root of negative numbers are not real numbers.
Answer:
24 Domain: s>=2 or s<=-2
25. 3x^2 +14x +10
26. x^2 -2x+5
Step-by-step explanation:
24. Domain is the input or s values
square roots must be greater than or equal to zero
s^2-4 >=0
Add 4 to each side
s^2 >=4
Take the square root
s>=2 or s<=-2
25. f(g(x)) stick g(x) into f(u) every place you see a u
f(u) = 3u^2 +2u-6
g(x) = x+2
f(g(x) = 3(x+2)^2 +2(x+2) -6
Foil the squared term
= 3(x^2 +4x+4) +2x+4-6
Distribute
= 3x^2 +12x+12 +2x+4-6
Combine like terms
=3x^2 +14x +10
26 f(g(x)) stick g(x) into f(u) every place you see a u
f(u) = u^2+4
g(x) = x-1
f(g(x) = (x-1)^2 +4
Foil the squared term
= (x^2 -2x+1) +4
= x^2 -2x+5
<span>x^2 - 4x - 12 = 0
factors
(x - 6)(x + 2) = 0
</span>Set (x - 6) and (x + 2)<span> equal to </span><span>0</span><span> and solve for </span><span>xx</span>.<span>
x - 6 = 0; x = 6
x + 2 = 0; x = -2
answer
x = -2 or x = 6</span>
