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ehidna [41]
3 years ago
10

Engineering students at Lancaster College last year received an average of $6,400 in scholarships and grants. This year, the ave

rage is $1,344. What is the percent of decrease in the average amount?
Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer:

79% decrease

Step-by-step explanation:

Subtract 6400-1344=5056

Find percent decrease (5056/6400)x100=79

79% decrease is our final answer

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Which equation are equivalent to Y equals2/3 X -4 when written in slope intercept form check all that apply
Neporo4naja [7]

Answer:

tg

Step-by-step explanation:

ggr

5 0
3 years ago
Can someone please help me​
defon

9514 1404 393

Answer:

  P = 50,000

  r = 0.08

  i = 0.02

  K = 4

  n = 20

  t = 5

Step-by-step explanation:

In this formula, r is the annual interest rate, 8% or 0.08. K is the number of times the interest is compounded in a year. Since interest is compounded quarterly, K = 4.

  r = 0.08

  i = r/K = 0.08/4

  i = 0.02

t is the number of years interest is compounded, so ...

 t = 5

  n = Kt = 4·5

  n = 20

P is the principal amount invested:

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7 0
3 years ago
In a group of 60 students, 14 students take Algebra 1,20 students take Algebra
melomori [17]

Answer

First we add all of the students that take either algebra 1, algebra 2 or both: 14+20+7= 41 which means out of 60 students 41 take either algebra 1, algebra 2 or both to find the rest of the students we subtract 41 from 6060-41= 19 answer: 19 students  don't take either subject

3 0
3 years ago
Read 2 more answers
If C(x) is the total cost incurred in producing x units of a certain commodity, then the average cost of producing x units of th
nataly862011 [7]

Answer:

x  =  2000 cameras

Step-by-step explanation:

C(x)     Total cost in producing  x units

C- = C(x) /x   Average cost of producing x units    x > 0

Cannon Precision Instrument

C (x)   Total monthly cost for producing x units of M1 cameras

is    C(x)  =  0.0025x²  + 80x  +  10000

Then average cost of producing x cameras M1 is

C-(x)  =  ( 0.0025x²  + 80x  +  10000)  /x

C-(x)  =   0.0025x  + 80  + 10000/x

Taking derivatives on both sides of the equation

C-´(x)   =  0.0025   -  10000/x²

Then

C-´(x)   = 0

( 0.0025x² - 10000 ) / x²   =  0

0.0025x² - 10000 =  0

x²  =  10000 /0.0025         x²  = 4000000

x  =  2000 cameras

8 0
3 years ago
2. Identify the solution to the system of equations graphed below.
12345 [234]
(-4, 1)

the solution is always where the two points meet!! :)
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