f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0
tan2(x) + √3[tan(x)] - tan(x) - √3 = 0
Factor into
[-1 + tan(x)]*[√3 + tan(x)] = 0
which means
[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0
Then
tan(x) = 1
tan-1(1) = pi/4 radians
For the other equation
[√3 + tan(x)] = 0
tan(x) = -√3
tan-1(-√3) = -pi/3
so that
x = pi/4 or -pi/3 in the interval [0, 2pi]
Step-by-step explanation:
(a) Sum is -4
4 + (-8)
4 - 8
-4
(b) Sum is 0
1 + (-1)
1 - 1
0
(c) Difference is 2
10 - 8
2
(d) Difference is -6
10 - 16
-6
squareroot
√1296 = 36
Let the percentage be x.
x% of 1296 = 36
=> 12.96x = 36
=> x = 36/12.96
=> x = 2.78% approx.
HOPE IT HELPS
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Future help- Use the law of sines and law of cosines to solve triangles.
Answer- D= 26° b= 5.48 d=2.57
