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adoni [48]
3 years ago
10

Hurry please will give brainlest will follow like and thank and give points please hurry and help.

Mathematics
1 answer:
Molodets [167]3 years ago
7 0
-2y-11=Z

n/4 -5=m

.................
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Solve for y.<br> 15y - -9y + -10y = 14<br> y =<br> Submit
Tems11 [23]

Answer:

I think y=1

Step-by-step explanation:

15y+9y= 24y

24y-10y=14y

divide 14y by 14 and get just y and divide 14 by 14 to get one

y=1

8 0
3 years ago
For the equation a(x+2)=-3x+b, if a=1 what value of b will make x=2
tiny-mole [99]

Answer:

10

Step-by-step explanation:

replace x with 2 and you will got the answer...

3 0
3 years ago
The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length
Lena [83]
In the problem, two legs measurement were given such as:
Leg 1 = 12 inches
Leg 2 = 15 inches

We need to solve for the third leg. Since it is a right triangle, we can use Pythagorean theorem in solving the missing leg:
c²=b²+a²

When we assume that the third leg is the "c", we can for the value such as:
c² = 12²+15²
c=19.21

When we assume that the third is either "a" or "b":
15² =a² + 12²
a=9

Then, the possible measurement of the third leg is 9 or 19.21.
The difference between the two possible answer is shown below:
Difference = 19.21 -9 = 10.21
Difference =10.21
6 0
3 years ago
find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM​
Snezhnost [94]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

  • To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

draw \: CE \: \parallel \: AD \:  \\ and \: CD \: \perp \: AE

Now , we can clearly see that AECD is a parallelogram !

\therefore AE = CD = 13 cm

Now ,

AB = AE + BE \\\implies \: BE =AB -  AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm

Now , In ∆ BCE ,

semi \: perimeter \: (s) =  \frac{15 + 15 + 12}{2}  \\  \\ \implies \: s =  \frac{42}{2}  = 21 \: cm

Now , by Heron's formula

area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

Also ,

area \: of \: \triangle \:  =  \frac{1}{2}  \times base \times height \\  \\\implies 18 \sqrt{21} =  \: \frac{1}{\cancel2}  \times \cancel12  \times height \\  \\ \implies \: 18 \sqrt{21}  = 6 \times height \\  \\ \implies \: height =  \frac{\cancel{18} \sqrt{21} }{ \cancel 6}  \\  \\ \implies \: height = 3 \sqrt{21}  \: cm {}^{2}

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

Area \: of \: trapezium =  \frac{1}{2}  \times(sum \: of \:parallel \: sides) \times height \\  \\ \implies \:  \frac{1}{2}  \times (25 + 13) \times 3 \sqrt{21}  \\  \\ \implies \:  \frac{1}{\cancel2}  \times \cancel{38 }\times 3 \sqrt{21}  \\  \\ \implies \: 19 \times 3 \sqrt{21}  \: cm {}^{2}  \\  \\ \implies \: 57 \sqrt{21}  \: cm {}^{2}

hope helpful :D

6 0
2 years ago
What is 22/9 as a mixed number
sergiy2304 [10]
If you do 22÷9 and see the hole number: 2. Then do 2 x 9 and you get 18. Now do 22-18 and you get 4. So do 2 4/9. Always have the denominator stay the same.
5 0
3 years ago
Read 2 more answers
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