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3 years ago

Which is an equation of an asymptote of the hyperbola?

Mathematics

1 answer:

Vikentia [17]3 years ago

3 0

Follow the method of rise over run and a is your answer

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I don’t understand how to do this problem and get all the other answers, if you can help me that would be great!

Alecsey [184]

Answer:

Step-by-step explanation:

You can’t just substitute 0 for θ. 0 is a constant, not a variable.

secθ = -13/5

cosθ = 1/secθ = -5/13

sin²θ = 1 - cos²θ = 144/169

sinθ = -12/13

cscθ = 1/sinθ = -13/12

tanθ = sinθ/cosθ = 12/5

cotθ = 1/tanθ = 5/12

8 0

2 years ago

What is 11.5 times 30

Lelechka [254]

Answer:

345

Step-by-step explanation:

6 0

2 years ago

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A toy car accelerates from rest to a velocity of 4.3 m/s. It does this over a time of 4 seconds. What is the car's acceleration?

Oxana [17]

Answer:

it will be 8.3 seconds try to add

4 0

2 years ago

If PQ bisects CX at point J, and if JX = 4y and CJ = y+9 find y

MAXImum [283]

Since PQ bisects CX at point J, JX=CJ

4y=y+9
-y -y
3y=9
divide by 3
y=3

3 0

3 years ago

Evaluate the given expression at x= -4<br> -3x + 2x^2 + 2

Mkey [24]

Answer:

$\huge{ \boxed{ \bold{ \text{46}}}}$

Step-by-step explanation:

If the value of variables of algebraic expression are given, the value of the term or expression can easily obtained by replacing the variables with numbers.

$\text{ \underline{ Given}} : \text{x = - 4}$

$\text{ \underline{ To \: find}} : \sf{value \: of \: - 3x + 2 {x}^{2} + 2}$

$\text{ Plug \: the \: value \: of \: x}$

$➝ \: \sf{ - 3 * (- 4 )+ 2 * {( - 4)}^{2} + 2}$

$\text{Remember!} : \text{Multiplying \: a \: negative \: integer \: by \: negative \: integer \: gives \: a \: positive \: integer.}$

➝ $\sf{12 + 2 * {( - 4)}^{2} + 2}$

$\text{Evaluate \: the \: power}$

➝ $\text{12 + 2 * 16 + 2}$

$\text{Multiply \: the \: numbers}$

➝ $\text{12 + 32 + 2}$

$\text{Add \: the \: numbers}$

$➝ \boxed { \text{46}}$

$\text{Hope \: I \: helped!}$

$\text{Best \: regards!}$

~ $\text{TheAnimeGirl}$

7 0

2 years ago

Read 2 more answers