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cestrela7 [59]
3 years ago
11

Isabella backed cookies for 3 hours. She spent the same amount of time baking each batch. It took her one eighth an hour to bake

each batch. How many batches of cookies did she bake?
Mathematics
1 answer:
katovenus [111]3 years ago
5 0

I believe it is 24 batches:

because there are 8/8 in one hour, so you multiply that by three. which would give you 24!

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Last month you went on three hikes. one hike was2 3/4 miles long one was 1 1/2 miles long and was 3 3/4 miles long. in decimal h
creativ13 [48]
2 3/4 = 2.75

1 1/2 = 1.5 

3 3.4 = 3.75

2.75 + 1.5 + 3.75 = 8

You hiked 8 miles last month in total.
8 0
3 years ago
Read 2 more answers
I need help please.
sweet-ann [11.9K]

Answer:

<u>Third Option</u>: y = \frac{5}{4}x

Step-by-step explanation:

Given the points on the graph, (4, 5) and (-4, -5):

In order to determine the equation of the given graph in slope-intercept form, y = mx + b:

Use the given points to solve for the slope:

Let (x₁, y₁) = (-4, -5)

(x₂, y₂) = (4, 5)

m = (y₂ - y₁)/(x₂ - x₁)

m = \frac{5 - (5)}{4 - (-4)}  = \frac{5 + 5}{4 + 4}  = \frac{10}{8} = \frac{5}{4}

Therefore, the slope of the line is: m = \frac{5}{4}.

Next, use one of the given points on the graph, (4, 5) to solve for the y-intercept, b:

y = mx + b

5 = \frac{5}{4} (4) + b

5 = 5 + b

5 - 5 = 5 - 5 + b

0 = b

Therefore, the linear equation in slope-intercept form is: y = \frac{5}{4}x.  The correct answer is Option 3.

8 0
3 years ago
I need help w/ this!! thank you
Fittoniya [83]
<h3><u>Answer:</u></h3>

\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}

<h3><u>Step-by-step explanation:</u></h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2  \\\\\bf\implies (2y+3)^2 \leq 1  \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1  \\\\\bf\implies 4y^2+9+12y - 1 \leq 0  \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0  \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup   \\\\\bf\implies y^2y+2y+y+2 \leq 0  \\\\\bf\implies y(y+2)+1(y+2)\leq 0  \\\\\bf\implies ( y+2)(y+1)\leq 0  \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}

<h3><u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
4 0
3 years ago
QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0
3 years ago
If x, y, and z are integers greater than 1, and (327)(510)(z) = (58)(914)(xy), then what is the value of x? (1) y is prime (2) x
Virty [35]

Answer:

1) 5

2) 5

Step-by-step explanation:

Data provided in the question:

(3²⁷)(5¹⁰)(z) = (5⁸)(9¹⁴)(x^y)

Now,

on simplifying the above equation

⇒ (3²⁷)(5¹⁰)(z) = (5⁸)((3²)¹⁴)(x^y)

or

⇒  (3²⁷)(5¹⁰)(z) = (5⁸)(3²⁸)(x^y)

or

⇒ (\frac{3^{27}}{3^{28}})(\frac{5^{10}}{5^8})z=x^y

or

⇒(\frac{5^2}{3})z=x^y

or

⇒\frac{5^2}{3}=\frac{x^y}{z}

we can say

x = 5, y = 2 and, z = 3

Now,

(1) y is prime

since, 2 is a prime number,

we can have

x = 5

2) x is prime

since 5 is also a prime number

therefore,

x = 5

8 0
3 years ago
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