8x12=96 4x34=136 136+96=232 232/2=116 answer=116
Answer:
Step-by-step explanation:
Alternate forms:
x^2 + y (y + 4) = 5
x^2 + y^2 + 4 y - 5 = 0
Solutions:
y = -sqrt(9 - x^2) - 2
y = sqrt(9 - x^2) - 2
Integer solutions:
x = ± 3, y = -2
x = 0, y = -5
x = 0, y = 1
Implicit derivatives:
(dx(y))/(dy) = -(2 + y)/x
(dy(x))/(dx) = -x/(2 + y)
Given the coordinates M (-6, -4) and T (9, 16)
If the coordinates are divided in the ratio 2:3 then a = 2, b = 3
The y coordinate of the point Q will be expressed as;
Y = ay1+by2/a+b
From the coordinates, y1 = -4 y2 = 16
Y = 2(-4)+3(16)/2+3
Y = -8+48/5
Y = 40/5
Y = 8
Hence the y-coordinate of the point Q is 8
Nononononono on onononononono ononononononononon
Answer:
Q (3.4)
Step-by-step explanation:
Midpoint for point (x1,y1) and (x2,y2) is given by
(x1+x2)/2, (y1+y2)/2.
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Given
one endpoint ( R(1, -1)
midpoint is M(2,1.5)
we have to find coordinates of endpoint Q
let Q(x,y)
Thus, for x coordinate of midpoint
2 = (1+x)/2
=> 2*2 = 1+x
=> 4 = 1+x
=> x = 4-1 = 3
x coordinate of midpoint m is 3
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for y coordinate of midpoint
1.5 = (-1+y)/2
=> 2*1.5 = -1+y
=> 3 = -1+ y
=> y = 3 + 1 = 4
y coordinate of midpoint m is 4
Thus, the coordinates of endpoint Q (3.4)
