V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
Answer:
800
Step-by-step explanation:
8*10*10=
8*10=
80*10=
800cm.
i broke up the problem. hope this helps!
Answer:
1.5*10^-2
Step-by-step explanation:
You mean 15/1000 written in scientific notation?
In this case, it would be- 1.5*10^-2.
Answer:
A)310.18g/mol
B)84.9947g/mol
C)108.01 g/mol
d)159.7g /mole(Approx)
e)Coc12 g/mol
f) A1(OH)3 g/mol
g)83.9949 g/mol
h)197.9 g/mol
i)18.01529 g/mol
Step-by-step explanation:
Hope u happy with my answer...
please mark me as brainlest
