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IrinaK [193]
3 years ago
15

If sin(x) = 0.28, what is cos(90° - x)

Mathematics
1 answer:
vlabodo [156]3 years ago
5 0
\bf \textit{Cofunction Identities}
\\\\
sin\left(\frac{\pi}{2}-\theta\right)=cos(\theta)
\qquad 
cos\left(\frac{\pi}{2}-\theta\right)=sin(\theta)
\\\\\\
tan\left(\frac{\pi}{2}-\theta\right)=cot(\theta)\qquad 
cot\left(\frac{\pi}{2}-\theta\right)=tan(\theta)
\\\\\\
sec\left(\frac{\pi}{2}-\theta\right)=csc(\theta)\qquad 
csc\left(\frac{\pi}{2}-\theta\right)=sec(\theta)

therefore, sin(x) = cos(90° - x).
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Diano4ka-milaya [45]

Remark

First of all you have to declare the meaning of g(f(x)) After you have done that, you have to make the correct substitution.

Givens

f(x) = 4x^2 + x + 1

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Discussion

What the given condition g(f(x)) means is that you begin with g(x). Write down g(x) = x^2 -  2

Wherever you see an x on either the left or right side of the equation, you put fix)

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<u>4x^2 + x + 1</u>

16x^4 + 4x^3 + 4x^2

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x = y + 7
x = 15 + 7
x = 22

<span>Liam has 15 and Leonard has 22. </span>
6 0
4 years ago
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