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Luba_88 [7]
3 years ago
12

If triangle def is rotated 180 degrees clockwise around the origin, what will be the coordinates of E’ in the image ?

Mathematics
2 answers:
arlik [135]3 years ago
7 0

Answer:

the answer is -3,-1

Step-by-step explanation:

Harlamova29_29 [7]3 years ago
5 0
E' (-3,-1)

When rotating 180° clockwise about the origin the coordinates of the image will be the same x and y numbers but the opposite sign of the pre-image. Using the above as an example, pre-image E is located at (3,1) so the rotated image would be E' (-3,-1). Pre-image D is located at (-1,3) so the rotated image would be D' (1,-3). Pre-image F is located at (2,-2) so the rotated image would be F' (-2,2).
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1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

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Round 6.225 to nearest tenth
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~Hope I Helped
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