Whats the last common multple of 2,5,6,9 and 9 is

1 answer:

3 0

"9 and 9?" Did you possibly mean {2, 5, 6, 9}?

The least common multiple of a set of numbers is the smallest integer that can be divided evenly by all of the numbers. In this case, when I saw the 9 and 5, I thought, "45!" but 45 is not evenly divisible by 2 or 6.

So, I tried 90. 90 is indeed divisible by {2, 5, 6, 9}, and is thus the LCM.

Look up and review "Least common multiple."

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I’d appreciate help ASAP please and thank you!

White raven [17]

<h3>Answer: Choice C) 40 </h3>

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Work Shown:

Plug in x = 0

$g(x) = 3^{2x}\\\\g(0) = 3^{2*0}\\\\g(0) = 3^{0}\\\\g(0) = 1\\\\$

This indicates that (0,1) is on the curve. This is the y intercept.

Do the same for x = 2

$g(x) = 3^{2x}\\\\g(2) = 3^{2*2}\\\\g(2) = 3^{4}\\\\g(2) = 81\\\\$

So we know that (2,81) is another point on this curve.

We need to find the slope of the line through (0,1) and (2,81) to get the slope of the secant line we want.

$m = \text{slope}\\\\m = \frac{\text{rise}}{\text{run}}\\\\m = \frac{\text{change in y}}{\text{change in x}}\\\\m = \frac{y_2-y_1}{x_2-x_1}\\\\m = \frac{g(2)-g(0)}{2-0}\\\\m = \frac{81-1}{2-0}\\\\m = \frac{80}{2}\\\\m = 40\\\\$

The slope of the line through (0,1) and (2,81) is m = 40. This value of m is exactly the slope of the secant line your teacher is asking for. This is why the answer is choice C.

5 0

3 years ago

Answer and round to the nearest tenth .<br> <img src="https://tex.z-dn.net/?f=2.1%5Csqrt%7B1.488%7D" id="TexFormula1" title="2.1

Illusion [34]

It is a good idea to get familiar with the operation of your calculator. If you're going to use on-line resources to work problems like this, you can make use of any of several good on-line calculators. Google and Bing search boxes will do calculations for you while observing all the rules of the Order of Operations.

The result of this computation is a number that begins 2.56.... Since the hundredths digit is more than 4, the tenths digit is rounded to the next higher value, from 5 to 6.

Rounded to tenths, 2.1√1.488 = 2.6