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svp [43]
2 years ago
10

Atrain travels at a speed of 58.6 km'hi Express this speeda.msb. m/min​

Mathematics
1 answer:
marishachu [46]2 years ago
8 0

Answer:

16.27

Step-by-step explanation:

if 1000m rep 1km

therefore :

58.6km/h in ms = 58.6km×1000/3600

=16.277 ms

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What is mA?<br> Enter your answer in the box.
Juliette [100K]

Answer:

X=3.75

Step-by-step explanation:

A=24.25

I guess

6 0
2 years ago
Evaluate the limit with either L'Hôpital's rule or previously learned methods.lim Sin(x)- Tan(x)/ x^3x → 0
Vsevolod [243]

Answer:

\dfrac{-1}{6}

Step-by-step explanation:

Given the limit of a function expressed as \lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3}, to evaluate the following steps must be carried out.

Step 1: substitute x = 0 into the function

= \dfrac{sin(0)-tan(0)}{0^3}\\= \frac{0}{0} (indeterminate)

Step 2: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the function

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ sin(x)-tan(x)]}{\frac{d}{dx} (x^3)}\\= \lim_{ x\to \ 0} \dfrac{cos(x)-sec^2(x)}{3x^2}\\

Step 3: substitute x = 0 into the resulting function

= \dfrac{cos(0)-sec^2(0)}{3(0)^2}\\= \frac{1-1}{0}\\= \frac{0}{0} (ind)

Step 4: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 2

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ cos(x)-sec^2(x)]}{\frac{d}{dx} (3x^2)}\\= \lim_{ x\to \ 0} \dfrac{-sin(x)-2sec^2(x)tan(x)}{6x}\\

=  \dfrac{-sin(0)-2sec^2(0)tan(0)}{6(0)}\\= \frac{0}{0} (ind)

Step 6: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 4

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ -sin(x)-2sec^2(x)tan(x)]}{\frac{d}{dx} (6x)}\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^2(x)sec^2(x)+2sec^2(x)tan(x)tan(x)]}{6}\\\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^4(x)+2sec^2(x)tan^2(x)]}{6}\\

Step 7: substitute x = 0 into the resulting function in step 6

=  \dfrac{[ -cos(0)-2(sec^4(0)+2sec^2(0)tan^2(0)]}{6}\\\\= \dfrac{-1-2(0)}{6} \\= \dfrac{-1}{6}

<em>Hence the limit of the function </em>\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3} \  is \ \dfrac{-1}{6}.

3 0
3 years ago
Find the product. Type your answer in the provided space. Do not use spaces in your answer. To demonstrate an exponent, use the
mel-nik [20]

Answer:

15x²6y² .................

3 0
3 years ago
The Bobcats football coach logged the following yardage gains and losses over four plays of a game.
lions [1.4K]
Answer:
9.8x - 11.1x
Explanation:
25 - 5.2 = 9.8x
0.9 - 12 = -11,1y

Notice: I’m not sure but if it wrong, you could replaced with 10x - 11y which be better answer
5 0
3 years ago
What are the domain and range of y=cot x? Select one choice for domain
Lostsunrise [7]

The domain is \boxed{x \neq n\pi}, where n is an integer.

  • This is because cot x = 1/tan(x), and if tan x = 0, then the fraction is undefined.

The range is <u>all real numbers</u>.

4 0
2 years ago
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