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NARA [144]
3 years ago
13

Domain Range

Mathematics
1 answer:
saul85 [17]3 years ago
6 0
No it's not.

There is no function that can produce this domain.
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Solve the following equation for x: 2x – 3y = 6.
Ksivusya [100]

Answer:

x=3/2y+3

Step-by-step explanation:

Let's solve for x.

2x−3y=6

Step 1: Add 3y to both sides.

2x−3y+3y=6+3y

2x=3y+6

Step 2: Divide both sides by 2.

2x2=3y+62

x=32y+3

6 0
3 years ago
What is an equation of the line that passes through the points (-5, 6) and<br> (7, 6)?
Schach [20]

Answer:

y = 6

Step-by-step explanation:

line of an equation: y = mx +c

where c is y-intercept, m is gradient and y and x are the y and x coordinates.

For finding the line of an equation we first find a gradient

gradient = (y2 -y1) / (x2 - x1)

so; (6-6) / (7-(-5)) = 0/12 = 0

next using any pair of coordinates we will find the c (y-intercept)

6= 0 (-5) + c

c = 6

so the equation will be

y = mx + c

(add the values you just found)

y = (0)x + 6 (since anything multiplied by 0 is 0 so we can write its like;)

y = 6

8 0
3 years ago
HELP!!!!! What number is missing in the solution to the system of equations? 4 x minus 3 y = 1. 5 x + 4 y = 9. ( 1 , )
Kay [80]

Answer:

(1,1)

i took the test

5 0
4 years ago
Y=-x+1<br> -2x-y=2 substitution
UNO [17]

Step-by-step explanation:

y=-x+1 \\ -2x-y=2given

- 2x-( - x + 1)=2  \\  - 2x + x - 1 = 2 \\  - x = 2 + 1 \\  - x = 3 \\ x = 3

put x

-2( - 3)-y=2  \\ 6 - y = 2 \\  - y = 2 - 6 \\  - y =  - 4 \\ y = 4

8 0
3 years ago
What is (f - g)(x)?<br> f (x) = 24 – 22 + 9<br> 9(2) = 23 + 3x2 + 12<br><br><br> (f - g)(x) = ???
bija089 [108]

Answer:

(f - g)(x) = x^4 - x^3 - 4x^2 - 3

Step-by-step explanation:

Subtract  g(x)=x^3 + 3x^2 + 12 from f(x)= x^4 - x^2 + 9

First, take the negative of every term (including the label g(x) ) of g(x), obtaining  -g(x) = -x^3 - 3x^2 - 12.

Now combine this result with f(x):

 f(x)= x^4 - 0x^3 - x^2 + 9

-g(x) =       - 1x^3 - 3x^2 - 12

---------------------------------------

(f - g)(x) = x^4 - x^3 - 4x^2 - 3

7 0
3 years ago
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