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kherson [118]
2 years ago
11

-5p + 39 = 3p+ -9 slove plz will give brainliest

Mathematics
2 answers:
BartSMP [9]2 years ago
6 0
P=6
-5p+39=3p+-9
-8p+39=-9
-8p=-48
p=6
natita [175]2 years ago
3 0

Answer:

p=6

If you need the work comment and ask

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(11x – 6x2 – 8)/(3x – 1)
kozerog [31]

Answer:

46.6

Step-by-step explanation:

have a good day

6 0
3 years ago
Solve the equation and give me how you solved it and the answer
Viktor [21]
Multiplying both sides by 3, we get (3/9)*(2m-16)=(2m+4). Next, we multiply both sides by 9 and expand to get 6x-48=18m+36. Subtracting 6x and 36 from both sides, we get 12x=-48-36=-84. After that, we divide both sides by 12 to get m=-7
4 0
3 years ago
What is 1,500mm + 15mm + 5m =
storchak [24]
1,520
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4 0
2 years ago
Martha is late for class, so she races her 75 kg body up a 4.0 meter flight of stairs in only 2.3 seconds. What is Martha’s powe
vovangra [49]

Answer:

1.3\cdot 10^3\text{ J}

Step-by-step explanation:

Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:

W=Fd, where F = force applied and d = distance that force is applied over.

*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by F_g=mg, where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, F_g=75\cdot 9.8=735\text{ N}. Since she raises her body 4.0 meters, the work done must be W=Fd=735\cdot 4=2940\text{ J}.

Since power is equal to work over time and t = 2.3 seconds, we have:

\displaystyle P=\frac{W}{t}=\frac{2940}{2.3}=\boxed{1278\text{ J}}\approx \boxed{1.3\cdot 10^3\text{ J}} (to two significant figures)

7 0
2 years ago
Umm can someone help with my angles homework. Pt 1.
Yuliya22 [10]

Answer:

I believe it is an acute angle

6 0
3 years ago
Read 2 more answers
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