THE MULTIPLE OF 3 ARE: 3 , 6 , 9 ,12
The 1st magazine costs either 3 or 6 or 9 , 12
The 2nd magazine costs <span>3 or 6 or 9 , 12
The value 12 is to be discarded , then are the sum of tall possibilities to get 12:
</span>mag 1st mag 2nd total
------------ ------------ --------
3 9 12
6 6 12
9 3 12
![f(x)=2x^2+6x-4\\](https://tex.z-dn.net/?f=f%28x%29%3D2x%5E2%2B6x-4%5C%5C)
Find f(-5) by substituting x = -5 in the equation.
![f(-5)=2(-5)^2+6(-5)-4\\f(-5)=2(25)-30-4\\f(-5)=50-34\\f(-5)=16](https://tex.z-dn.net/?f=f%28-5%29%3D2%28-5%29%5E2%2B6%28-5%29-4%5C%5Cf%28-5%29%3D2%2825%29-30-4%5C%5Cf%28-5%29%3D50-34%5C%5Cf%28-5%29%3D16)
Therefore, the answer is f(-5) = 16
Algebraic expression is the expression which consist the variables, coefficients and the constants. The expression for the condition given in the problem is
.
Given information
A cab driver is paid $6 plus $0.45 per mile driven.
Total number of total miles is <em>m.</em>
<h3>
Algebraic expression</h3>
Algebraic expression is the expression which consist the variables, coefficients and the constants. The algebraic expression are used to solve the condition based problems by expressing them into the algebraic form.
As the cab driver is paid $6 as the fixed amount of the taxi irrespective to the mile driven. Thus this is independent to the other variables and written as the constant in the expression.
As the total miles driven by the cab driver is<em> m</em>. The cost of the per mile driven the car is $0.45. Thus the expression for this condition can be given as,
![f(m)=0.45m+6](https://tex.z-dn.net/?f=f%28m%29%3D0.45m%2B6)
Hence, the expression for the condition given in the problem is
.
Learn more about the algebraic expression here;
brainly.com/question/953809
So the “certain number” will be S.
Since 2width + 2length, the first part would be 2 times 2 which is 4
The length is S - 3
We then have to multiply this by 2
So it is 2(S-3) which is 2S-6
So the answer is 4+2S-6 which is 2S-2
Answer:
equation 2into minus 3 into equation 1
8x+ 3y= -28
-3x-3y=18
----------------
5x=10
x =2
put value of y in equation 2
8 into 2+3y=-28
16+3y= -28
3y= -28+16
3y= -12
y= -4