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larisa86 [58]
3 years ago
7

The spinner below shows 10 equally sized slices. Maya spun the dial 20 times and got the following results. a) From Maya's resul

ts, comoute the experimental probabiltiy of landing on white. b) Assuming that the spinner is fair, compute the theoretical probability of landing on white. c) Assuming that the spinner is fair, choose the statement below that is true

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
3 0
A) 1/2 bc half of the spinner is white 
B) 1/2, 0.5
C) is the last one, the bottom one to be right
ruslelena [56]3 years ago
3 0
A) is 11 out of 20
B) is 1/2
C) the second choice
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Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches.
Maurinko [17]

Answer:

Q3 = 65.7825.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 63.6, \sigma = 2.5

Find the value of the quartile Q3. (Hint: Q3 has an area of 0.75 to its left.)

This is the value of X when Z has a pvalue of 0.75. So it is X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 63.6}{2.5}

X - 63.6 = 0.675*2.5

X = 65.7825

Q3 = 65.7825.

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3 years ago
Tank a has a capacity of 9.5 galloons 6 1/3 gallons of the tanks water are poured out how many gallons of water are left in the
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= 9 \frac{1}{2} - 6 \frac{1}{3} \\ = 9 \frac{3}{6} - 6 \frac{2}{6}
= 3 \frac{3 - 2}{6} \\ = 3 \frac{1}{6}

3 1/6 gallons of water are left in the tank.
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the total cost would be $89.50

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