Answer:
r=4sin(theta)
Step-by-step explanation:
x=4sin^2(theta) y=4sin(theta)cos(theta
theta=arcsin((sqrtx)/2)
y=4sin(arcsin(sqrtx/2))cos(arcsin(sqrtx/2))
graph each to see they line up
Answer:
a
Step-by-step explanation:
give
For either square root to exist, you require that
. This is true for all
, since
is always non-negative. This means the domain of
as a function of
is all real numbers, or
or
.
Now, because
is non-negative, and the smallest value it can take on is 7, it follows that the minimum value for the positive square root must be
, while the maximum value of the negative root must be
. This means the range is
, or
, or
![(-\infty,-\sqrt7]\cup[\sqrt7,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-%5Csqrt7%5D%5Ccup%5B%5Csqrt7%2C%5Cinfty%29)
.
Answer:
~460032.8
Step-by-step explanation:
Essentially, when this is written out, we get:
6 ÷ 2 × 3 × 100 × 700 ÷ 1.37 × 0.778 + 0.778913 × 100 × 10 × 1.77 × 444444.47 ÷ 7777777.0999 + 100
Order of operations says to do multiplication and division first, so let's calculate 6 ÷ 2 × 3 × 100 × 700 ÷ 1.37 × 0.778 separately:
6 ÷ 2 = 3
3 × 3 = 9
9 × 100 = 900
900 × 700 = 630000
630000 ÷ 1.37 = 459854
459854 × 0.778 = 357766
Now calculate 0.778913 × 100 × 10 × 1.77 × 444444.47 ÷ 7777777.0999:
0.778913 × 100 × 10 × 1.77 × 444444.47 = 612744929
612744929 ÷ 7777777.0999 ≈ 78.78
Add these all up:
357766 + 78.78 + 100 ≈ 460032.8
To solve problem 1 what you need to do is figure out how many miles the girls have walked so far and then subtract that from the total distance they must complete.
3/4-(3/10+1/4)
Step 1:Change the denominators so that way they are all the same
3/4=15/20
3/10=6/20 15/20-(6/20+5/20)
1/4=5/20
Step 2: Begin solving the problem
6/20+5/20=11/20
15/20-11/20=4/20
Step 3: Simplify your answer
4/20=1/5
Step 4 (is optional): Write your answer in a complete statement
The three girls walk 1/5mile together to school
Answer: A
I hope this is correct and if not I apologize for giving false information.
